Page 225 - Process Equipment and Plant Design Principles and Practices by Subhabrata Ray Gargi Das
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7.3 Design illustration  223




               Steps of calculation
               The saturated air enthalpy curve (AB) is drawn in Fig. 7.7 for the range 20e50 C using data from

               Table P7.1.

                  Saturated air enthalpy (on line AB) at T amb;WBT ¼ 29 C, is read; h c ¼ 22.479 kcal/kg dry air.
               1. Point C, the air entry location on the operating line is located on the graph corresponding to

                  (T c ¼ 33 C, h c ¼ 22.479 kcal/kg dry air)
                                 0
               2. A straight line CD is drawn that touches the curve AB. Slope of this line corresponds to the
                  theoretically minimum air requirement, i.e., ðL=GÞ  .
                                                           max
                  The slope of the operating line must be lower than ðL=GÞ  .
                                                                  max
               3. Referring to Table 7.2, we note that for “Film Fill” 1.5 < ðL=GÞ < 2 is recommended.
                  Accordingly, a value of ðL=GÞ is assumed as say 1.5.
               4. An operating line CD is drawn with a slope of ðL=GÞ. The end point D of the operating line is

                  located corresponding to water temperature T h ¼ 45 C. Corresponding enthalpy (h D ) of air
                  exiting the tower is: h D ¼ h C þðL=GÞðT h  T c Þ e.g., for ðL=GÞ¼ 1.5,
                  h D ¼ 22:479 þ 1:5  ð45   33Þ¼ 40:479 kcal/kg dry air
               5. The  KaV  corresponding to the ðL=GÞ value assumed is the area CDD’B that represents  R  Th  dT  .
                       L                                                                Tc ðh  hÞ
                                                                                            0
                  The integral can be evaluated by the Chebeyshev’s method as suggested by CTI. For ðL=GÞ¼ 1.5,
                  KaV
                   L  ¼ 1.7858.
               6. For different values of ðL=GÞ, the corresponding  KaV  is calculated following Step 5e7. The results
                                                          L
                  are presented in Table P7.2.
         Table P7.2  KaV  [  R Th  dT  , from Merkel equation.
                    L     Tc ðh LhÞ
                              0
         ðL=GÞ   1.50    1.55    1.60     1.65    1.70     1.75    1.80    1.85     1.90    1.95     2.00
         KaV     1.7858  1.8558  1.9326   2.0181  2.1138   2.2216  2.3445  2.4861   2.6515  2.8482   3.0869
          L


                  ðL=GÞ  corresponds to the operating condition when the chosen fill provides the required  KaV
                       op                                                                    L
                i.e., the  KaV  from the Merkel equation and that from the fill characteristics match. ðL=GÞ  is therefore
                       L                                                              op
               found by drawing the lines for ðL=GÞ vs.  KaV  from the fill characteristics equation and from Table P7.2
                                                 L
               on the same graph (Fig. P7.1) and locating the intersection point. The lines intersect at
               ðL=GÞ op  ¼ 1.587 in this design example.
                  Note: Although earlier, it has been mentioned that the tower characteristics are plotted with log-log
               axes, Fig. P7.1 has been drawn with the linear axis as the range of variation is small.
               Fan power calculation
                                                            3  2                          2
               For ðL=GÞ  ¼ 1.587 and C ¼ 6000 mt/hr, L ¼ 15 m /m hr, G ¼ 15/1.587 ¼ 9.45 mt/m hr dry
                        op
               airflow.
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