Page 298 - Process Modelling and Simulation With Finite Element Methods
P. 298

Coupling Variables Revisited           285

          By comparison, the Subdomain settings are still pedestrian:

           Subdomain Mode
                  Select mode gl (geoml domain 1)
                  Set r=O,  da=l, F=(nl-exp(-v))/tau-ba+nl*da
              0
                  Apply/OK
                  Select mode g2 (geom2 domain 1) Set r=O 0, da=O, F=n2-N1*N2
                  APPlY
              0   OK
          Now for the boundary conditions.  Neutral are needed. Pull down the Boundary
          menu and select Boundary Settings.

              Boundarv Mode
                 0   Mode gl: geoml domain 1,2 Select Neumann, G=O
                     Mode g2: geom2 domain 1,2,3,4  Select Neumann, G=O
                     APPlY
                 0   OK
          In Mesh mode, accept the standard mesh for geom2, which gives for mode g2
          (415  nodes,  768  elements)  and  in  mode  gl,  set  number  of  elements  per
          subdomain  to  1  100,  to  give  251  nodes,  250  elements.  Solve  using  the
          Stationaty Nonlinear solver.  The solution should appear as in Figure 7.15.

                  COIDl oaia  “I  (“I)  Y  Data  “1 (“1)
          80
          70
          60
          m
          40
          30
          m
          10
          0
          10
             o   5m   moo   1500   moo   25m
          Figure 7.15  Solution nl(v) to (7.27).  Left: l-D solution.  Right: 2-D solution for extrusion variable
          N2=nl (v2,vl-v2).
          Parametric  continuation  will  permit  us  to  persevere  out  to  ~=1.175 before
          convergence is lost.  Yet  the solution in Figure 7.15 hardly  seems plausible  -
          nearly  all  the  particles  “gang  up”  in  the  maximum  volume  of  the  truncated
          infinite  domain  - hardly  likely to  have  infinitesimal truncation error.  These
          particles would aggregate up to the next higher “bin” if they were permitted.  So
          this is not likely a stationary solution to the full problem.
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