Page 264 - Schaum's Outline of Theory and Problems of Advanced Calculus
P. 264

CHAP. 10]  LINE INTEGRALS, SURFACE INTEGRALS, AND INTEGRAL THEOREMS             255

                                                                    þ
                     10.28. Prove that a necessary and sufficient condition that  A   dr ¼ 0 for every closed curve C is that
                           r  A ¼ 0 identically.                     C
                           Sufficiency.  Suppose r  A ¼ 0.  Then by Stokes’ theorem
                                                      þ       ðð
                                                                ðr   AÞ  n dS ¼ 0
                                                        A   dr ¼
                                                      C
                                                              S
                           Necessity.
                                     þ
                              Suppose  A   dr ¼ 0around every closed path C, and assume r  A 6¼ 0 at some point P.  Then
                                      C
                           assuming r  A is continuous, there will be a region with P as an interior point, where r  A 6¼ 0.Let S be
                           asurface contained in this region whose normal n at each point has the same direction as r  A, i.e.,
                           r  A ¼  n where   is a positive constant. Let C be the boundary of S. Then by Stokes’ theorem
                                                þ       ðð              ðð
                                                          ðr   AÞ  n dS ¼    n   n dS > 0
                                                  A   dr ¼
                                                 C
                                                         S              S
                                                      þ
                           which contradicts the hypothesis that  A   dr ¼ 0 and shows that r  A ¼ 0.
                                                       C                                     ð P 2
                              It follows that r  A ¼ 0 is also a necessary and sufficient condition for a line integral  A   dr to be
                           independent of the path joining points P 1 and P 2 .               P 1
                     10.29. Prove that a necessary and sufficient condition that r  A ¼ 0 is that A ¼r .
                           Sufficiency.  If A ¼r ,then r  A ¼r   r  ¼ 0 by Problem 7.80, Chap. 7, Page 179.
                           Necessity.                    þ                             ð
                              If r  A ¼ 0,thenby Problem 10.28, A   dr ¼ 0 around every closed path and  A   dr is independent
                                                                                        C
                           of the path joining two points which we take as ða; b; cÞ and ðx; y; zÞ.  Let us define
                                                      ð          ð
                                                       ðx;y;zÞ   ðx;y;zÞ
                                                                     A 1 dx þ A 2 dy þ A 3 dz
                                              ðx; y; zÞ¼  A   dr ¼
                                                       ða;b;cÞ   ða;b;cÞ
                           Then
                                                                ð
                                                                 ðxþ x;y;zÞ
                                                                       A 1 dx þ A 2 dy þ A 3 dz
                                            ðx þ  x; y; zÞ   ðx; y; zÞ¼
                                                                 ðx;y;zÞ
                              Since the last integral is independent of the path joining ðx; y; zÞ and ðx þ  x; y; zÞ,wecan choose the
                           path to be a straight line joining these points so that dy and dz are zero.  Then
                                                         1  ð  ðxþ x;y;zÞ
                                                                                        0 <  < 1
                                    ðx þ  x; y; zÞ   ðx; y; zÞ
                                             x         ¼   x ðx;y;zÞ  A 1 dx ¼ A 1 ðx þ    x; y; zÞ
                           where we have applied the law of the mean for integrals.
                              Taking the limit of both sides as  x ! 0gives @ =@x ¼ A 1 .
                              Similarly, we can show that @ =@y ¼ A 2 ; @ =@z ¼ A 3 :
                                                    @    @   @
                                                               k ¼r :
                                                    @x   @y  @z
                              Thus, A ¼ A 1 i þ A 2 j þ A 3 k ¼  i þ  j þ
                     10.30. (a) Prove that a necessary and sufficient condition that A 1 dx þ A 2 dy þ A 3 dz ¼ d ,an exact
                           differential, is that r  A ¼ 0 where A ¼ A 1 i þ A 2 j þ A 3 k.
                           (b) Show that in such case,
                                    ð                         ð
                                     ðx 2 ;y 2 ;z 2 Þ          ðx 2 ;y 2 ;z 2 Þ
                                           A 1 dx þ A 2 dy þ A 3 dz ¼  d  ¼  ðx 2 ; y 2 ; z 2 Þ   ðx 1 ; y 1 ; z 1 Þ
                                     ðx 1 ;y 1 ;z 1 Þ          ðx 1 ;y 1 ;z 1 Þ
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