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                                                                                     Failures Resulting from Static Loading  253
                                               Interference—General
                                               In the previous segments, we employed interference theory to estimate reliability when the
                                               distributions are both normal and when they are both lognormal. Sometimes, however, it
                                               turns out that the strength has, say, a Weibull distribution while the stress is distributed
                                               lognormally. In fact, stresses are quite likely to have a lognormal distribution, because the
                                               multiplication of variates that are normally distributed produces a result that approaches
                                               lognormal. What all this means is that we must expect to encounter interference problems
                                               involving mixed distributions and we need a general method to handle the problem.
                                                  It is quite likely that we will use interference theory for problems involving distri-
                                               butions other than strength and stress. For this reason we employ the subscript 1 to
                                               designate the strength distribution and the subscript 2 to designate the stress distribu-
                                               tion. Figure 5–32 shows these two distributions aligned so that a single cursor x can be
                                               used to identify points on both distributions. We can now write
                                                             Probability that

                                                             stress is less  = dp(σ < x) = dR = F 2 (x) dF 1 (x)
                                                             than strength
                                               By substituting 1 − R 2 for F 2 and −dR 1 for dF 1 , we have

                                                                       dR =−[1 − R 2 (x)] dR 1 (x)
                                               The reliability for all possible locations of the cursor is obtained by integrating  x
                                               from −∞ to ∞; but this corresponds to an integration from 1 to 0 on the reliability R 1 .
                                               Therefore
                                                                             0

                                                                     R =−     [1 − R 2 (x)] dR 1 (x)
                                                                            1
                                               which can be written
                                                                                   1

                                                                         R = 1 −    R 2 dR 1                   (5–46)
                                                                                  0

                       Figure 5–32             f (S)
                                               1
                       (a) PDF of the strength                         dF (x) = f (x) dx
                                                                         1   1
                       distribution; (b) PDF of the
                       load-induced stress
                       distribution.

                                                                                   S
                                                                      dx
                                                    (a)

                                                         x
                                                                     Cursor
                                               f ( )
                                               2


                                                      F (x)
                                                       2
                                                                       R (x)
                                                                        2

                                                    (b)
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