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                                                                                          Shafts and Shaft Components  385
                                               which can be rewritten as
                                                                         2
                                                              (m 1 δ 11 − 1/ω )y 1 + (m 2 δ 12 )y 2 + (m 3 δ 13 )y 3 = 0
                                                                                   2
                                                              (m 1 δ 21 )y 1 + (m 2 δ 22 − 1/ω )y 2 + (m 3 δ 23 )y 3 = 0  (a)
                                                                                              2
                                                              (m 1 δ 31 )y 1 + (m 2 δ 32 )y 2 + (m 3 δ 33 − 1/ω )y 3 = 0
                                               Equation set (a) is three simultaneous equations in terms of y 1 , y 2 , and y 3 . To avoid the
                                               trivial solution y 1 = y 2 = y 3 = 0, the determinant of the coefficients of y 1 , y 2 , and y 3
                                               must be zero (eigenvalue problem). Thus,

                                                         #            2                              #
                                                         # (m 1 δ 11 − 1/ω )  m 2 δ 12      m 3 δ 13  #
                                                         #                                           #
                                                                                    2
                                                                                                     #
                                                         #               (m 2 δ 22 − 1/ω )           # = 0     (7–26)
                                                              m 1 δ 21                      m 3 δ 23
                                                         #
                                                         #                                           #
                                                              m 1 δ 31       m 2 δ 32
                                                         #                              (m 3 δ 33 − 1/ω )
                                                                                                   2 #
                                               which says that a deflection other than zero exists only at three distinct values of ω, the
                                               critical speeds. Expanding the determinant, we obtain
                                                                 3                            2

                                                              1                            1
                                                                  − (m 1 δ 11 + m 2 δ 22 + m 3 δ 33 )  +· · · = 0  (7–27)
                                                             ω 2                          ω 2
                                                                                               2
                                                                                                              2
                                                                                                     2
                                               The three roots of Eq. (7–27) can be expressed as  1/ω ,  1/ω , and  1/ω . Thus
                                                                                               1     2        3
                                               Eq. (7–27) can be written in the form
                                                                  1    1     1    1     1    1

                                                                     −         −          −      = 0
                                                                  ω 2  ω 2   ω 2  ω 2  ω 2  ω 2
                                                                        1          2          3
                                               or
                                                                   3                        2
                                                                1        1    1    1    1

                                                                    −      +    +            + ··· = 0         (7–28)
                                                               ω 2      ω 2  ω 2  ω 2   ω 2
                                                                         1    2    3
                                               Comparing Eqs. (7–27) and (7–28) we see that
                                                                 1    1    1
                                                                   +    +    = m 1 δ 11 + m 2 δ 22 + m 3 δ 33  (7–29)
                                                                ω 2  ω 2  ω 2
                                                                  1    2    3
                                                                                                                 2
                                               If we had only a single mass m 1 alone, the critical speed would be given by 1/ω =
                                               m 1 δ 11 . Denote this critical speed as  ω 11 (which considers only  m 1 acting alone).
                                               Likewise for m 2 or m 3 acting alone, we similarly define the terms 1/ω 2 22  = m 2 δ 22 or
                                               1/ω 2  = m 3 δ 33 , respectively. Thus, Eq. (7–29) can be rewritten as
                                                  33
                                                                   1    1    1     1     1    1
                                                                     +    +     =    +     +                   (7–30)
                                                                  ω 2   ω 2  ω 2  ω 2   ω 2  ω 2
                                                                    1    2    3    11    22    33
                                                                                                                   2
                                                                                                          2
                                                                                                   2
                                               If we order the critical speeds such that ω 1 <ω 2 <ω 3 , then 1/ω   1/ω , and 1/ω .
                                                                                                   1      2        3
                                               So the first, or fundamental, critical speed ω 1 can be approximated by
                                                                        1 .   1    1     1
                                                                          =     +     +                        (7–31)
                                                                        ω 2  ω 2   ω 2  ω 2
                                                                         1    11    22    33
                                               This idea can be extended to an n-body shaft:
                                                                                  n
                                                                            1 .  $   1
                                                                               =                               (7–32)
                                                                            ω 2     ω 2
                                                                             1   1=1  ii
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