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134    DEFORMABILITY OF DISCRETE ELEMENTS

              of this vector changes with the deformation of the discrete element. The orientation of
              the initial frame is defined by a triad of non-unit vectors that are in general not parallel
              to the respective axes of the Cartesian coordinate system. In addition, these vectors
              are in general not orthogonal to each other. Initially, this frame coincides with the
              initial frame. As the body deforms, this frame begins to differ from the initial frame.
              As this frame is obtained through deformation of the initial frame, it is in further text
              referred to as a deformed initial frame. A deformed initial frame is defined by a triad
              of non-orthogonal non-unit vectors:

                                                ˘ ˘ ˘
                                               (i, j, k)                         (4.10)
            The global, local and initial frames are inertial frames, while the deformed local frame
            and deformed initial frame are non-inertial frames.
              The relationship between a local and deformed local frame can be obtained using the
            deformation gradient. In the global frame, the deformation gradient tensor can be written
            using the following matrix:
                                                     ∂u    ∂u       ∂u
                                                                       
                                                 1 +
                                                  ∂x    ∂y       ∂z  
                               x + u(x, y, z)                          
                                                   ∂v        ∂v     ∂v
                                                                       
                  F =∇f =∇  y + v(x, y, z)  =         1 +                    (4.11)
                             
                                           
                                                  ∂x        ∂y     ∂z  
                               z + w(x, y, z)                          
                                                   ∂w      ∂w        ∂w
                                                                       
                                                                 1 +
                                                   ∂x      ∂y        ∂z
            The same deformation gradient tensor can be written in the local frame using the follow-
            ing matrix:
                                                     ∂u    ∂u       ∂u
                                                                       
                                                 1 +
                                                  ∂x    ∂y       ∂z  
                               x + u(x, y, z)                          
                                                   ∂v        ∂v     ∂v
                                                                       
                             
                  F =∇f =∇  y + v(x, y, z)  =         1 +                    (4.12)
                                           
                                                  ∂x        ∂y     ∂z  
                               z + w(x, y, z)                          
                                                  ∂w      ∂w        ∂w  
                                                                 1 +
                                                   ∂x      ∂y        ∂z
            Triad vectors of the local frame are parallel to the axes of the corresponding Cartesian
            coordinate system, and can be expressed in a matrix form:
                                                        
                                                         1
                                       i = 1i + 0j + 0k =   0                  (4.13)
                                                         0
                                                        
                                                         0
                                                         1
                                      j = 0i + 1j + 0k =                       (4.14)
                                                         0
                                                        
                                                         0
                                                         0
                                      k = 0i + 0j + 1k =                       (4.15)
                                                         1
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