Page 80 - Thermodynamics of Biochemical Reactions
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4.10 Calculation of  Standard Transformed  Gibbs Energies of  Species   75


         Thus the fundamental equation for the transformed Gibbs energy can be written
         as
                                         "
                   dC' = -SdT+  VdP + c pidni
                                        i=  1
                          - n,(H) ((-il)   +)     dT-  RTln(l0)dpH

                                           P,(n:},pH
                                        Nr
                       = -SdT+  VdP + 1 pidni - n,(H)dp(H+)
                                        i= 1
         where the term in parentheses is the total differential of the chemical potential of
         hydrogen ions (see equation 4.1-10).
            The summation in equation 4.10-3 can be written in terms of species exclusive
         of  the  hydrogen  ion  because  when  species  in  a  pseudoisomer  group  are  in
         equilibrium at a specified pH, these species have the same transformed chemical
         potential.

                                          Ns-1
                      dG' = -SdT+  VdP +  C  &dnj - n,(H)dp(H+)         (4.10-4)
                                           j= 1
         where N, is the number of different species.
            Now the inverse Legendre transform given in equation 4.10-1 is needed. The
         differential of  the Gibbs energy is given by
                         dG = dG' + n,(H)dp(H+) + p(H+)dn,(H)           (4.10-5)
         Substituting equation 4.10-4 into this equation yields

                                          N,-  1
                      dG = -SdT+  VdP + c  pldnj + p(H+)dn,(H)          (4.10-6)
                                          j= 1
         The amount of the hydrogen component n,(H)  in the system is given by equation
         4.1-2, and so equation 4.10-6 can be written as
                                           N,
                       dG = -SdT+  VdP + c (pi + NH(j)p(H+)}dnj         (4.10-7)
                                          j= 1
         The term in braces is the chemical potential of ion j:

                                  pj =  + NH(j)p(H+)                    (4.10-8)
         and so equation 4.1-5 is obtained as expected.
             If the apparent equilibrium constant K'  for an enzyme-catalyzed reaction has
         been determined at 298.15K and AfG'O values can be calculated at the experimen-
         tal pH and ionic strength using known functions of pH and ionic strength for all
         the reactants but one, the A,G"  of  that reactant  under the experimental condi-
         tions  can  be  calculated  using equation 4.4-2.  So far  functions  of  pH and ionic
         strength  that yield A,G"  are have  been published for  131 reactants at 298.15 K
         (Alberty, 200 1  f).
             When the reactant of  interest consists of a single species, Af Go(I = 0) for this
         species at 298.1 5 K can be calculated using equation 4.10-8 in the following form
         (see equation 4.4-10):
                       A,GY(I  = 0) = AfG'O(pH,I) - N,(j)RTln(lO)pH

                                    +  2.91482(z;  - NH(j))I1I2         (4.10-9)
                                            1 + 1.6Z1'2

         A program calcGeflsp has been written to produce output in the form of equation
         3.8-1 for  a  reactant  made  up  of  one species. It  is  given  in  the  package  Basic-
         BiochemData2.
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