Page 53 - Using ANSYS for Finite Element Analysis A Tutorial for Engineers
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40  •   Using ansys for finite element analysis
                Therefore, substituting in [B] matrix,


                                   −  125  0  250  0   −125    0 
                        B [] =  1     0  −250  0  0     0    250   
                            62500
                                     −250  −125  0  250  250  −125 


                For plane stress, the [D] matrix is conveniently expressed here as:


                                                       
                                             1 u    0  
                                         E             
                                   D [] =     u  1  0  
                                       (1 −u 2 )   1 −u 
                                             00        
                                                    2  


                With ʋ = 0.3 and E = 210 GPa, we obtain


                                             1  0 3 .  0  
                                 D [] =  210000   03 .  1  0   
                                        .
                                       091
                                              0  0  035  
                                                       .
                                         −125  0    −250
                                                        
                                           0   −250  −125
                                                            1  0 3.  0 
                        T       210000    250  0     0              
                          D
                                                            .
                Then,  B [] []=                           03  1    0
                              62500 091)   0    0    250              
                                   (.
                                                        
                                                                     .
                                                            0  0   035
                                         −125  0    2 250           
                                                        
                                           0  250  − 125 
                                             −125  −37 5  −875 
                                                            .
                                                      .
                                                              
                                                            .
                                              −75  −250  −43 75 
                                T
                                  D
                              B
                           ∴[] [] = 3 6923    250  75    0    
                                       .
                                              0    0     87 5  
                                                            .
                                             −125 −37 5 .  875 .  
                                                  −
                                                              
                                              75  250  −43 75  
                                                            .
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