Page 70 - Fluid Power Engineering
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48   Chapter Four




                   y
                        x                   Pressure= p 0 r  Pressure= p 2 r

                                   dr
                          W
                                  r
                 ν 1
                                                                2bWr


                                                             ν 1
                                                             bWr

                                                          ν 1
                                               ν 1
                                                         Wr

              FIGURE 4-11 Schematic of rotor disk theory. Axis of rotation of the rotor is the
              x-axis; the wind direction is along the x-axis. The cross section of the rotor at
              a distance r from the center is shown in the right. Blades move down with
              tangential velocity; wind acquires a tangential velocity in the opposite
                                         1
              direction. (Adapted from Burton et al. .)

                 According to Newton’s second law, this change in angular mo-
              mentum of wind must be accompanied by a torque. Stated differently,
              the geometry of the flow is such that wind is forced to acquire tangen-
              tial component of velocity (forced to acquire angular momentum). Us-
              ing Newton’s second law, this forced increase in angular momentum
              will demand that the blade/rotor deliver a torque to wind. According
              to Newton’s third law, wind will then deliver an equal but opposite
              torque to the blade/rotor. Angular momentum is the cross-product
              of the radius vector and the tangential momentum vector. The power
              that is delivered to the rotor is the torque multiplied by the angular
              velocity.


                                                r
                            Angular momentum = ¯ × m¯v             (4-3)
               Q = Torque = Rate of change of angular momentum = ˙mv t r  (4-4)

                       P = Power = Torque . angular velocity = Q .ω  (4-5)

              The rate of mass flow through an annulus ring of the rotor is:


                     δ ˙m = ρv 1 δA = ρv 1 2πrδr = ρv 0 (1 − a) 2πrδr  (4-6)
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