Page 127 - Characterization and Properties of Petroleum Fractions - M.R. Riazi
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            AT029-Manual
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                                                           3. CHARACTERIZATION OF PETROLEUM FRACTIONS 107
                               TABLE 3.12—Prediction of ASTM D 86 from SD for a petroleum fraction of Example 3.5.
                                                                Eqs. (3.18) and (3.19)  Eqs. (3.25)–(3.28)
                           Vol%     ASTM D 2887  ASTM D 86   ASTM D 86              ASTM D 86
                           distilled  (SD) exp, C  exp, C     calc, C     AD, C       calc, C   AD, C
                                                                 ◦
                                           ◦
                                                     ◦
                                                                                                   ◦
                                                                                         ◦
                                                                             ◦
                           10          33.9         56.7       53.2        3.4         53.5      3.2
                           30          64.4         72.8       70.9        1.9         68.2      4.5
                           50          101.7        97.8       96.0        1.8         96.8      1.0
                           70          140.6       131.7      131.3        0.4        132.5      0.9
                           90          182.2       168.3      168.3        0.0        167.8      0.6
                           Overall AAD, C                                  1.5                   2.0
                                     ◦
                6.761560 − 0.987672 log 10  P
            Q =                             (P < 2 mm Hg)         where
                   3000.538 − 43 log 10  P                                                              P
                                                                           T = T b − 1.3889 F (K W − 12) log 10

                                                                            b
                5.994296 − 0.972546 log 10  P                                                           760
            Q =                             (2 ≤ P ≤ 760 mm Hg)
                  2663.129 − 95.76 log  P                         where all the parameters are defined in Eq. (3.29). The main
                                   10
                                                                  application of this equation is to estimate boiling points at
                6.412631 − 0.989679 log 10  P                     10 mm Hg from atmospheric boiling points. At P = 10
            Q =                             (P > 760 mm Hg)
                   2770.085 − 36 log  P                           mm Hg, Q = 0.001956 and as a result Eq. (3.30) reduces to
                                  10
                                                                  the following simple form:
                                         P
            T b = T + 1.3889F(K W − 12) log

                 b                    10  760                                                0.683398T
                                                                 (3.31)    T(10 mm Hg) =             b
                                                                                                       −4
                                                                                         1 − 1.63434 × 10 T b
            F = 0                      (T b < 367 K) or when K W
                                                                  in which T is calculated from T b as given in Eq. (3.30) and

                                                                           b
                                         is not available
                                                                  both are in kelvin. Temperature T (10 mm Hg) is the boiling
                                       (367 K ≤ T b ≤ 478 K)      point at reduced pressure of 10 mm Hg in kelvin. By assum-
            F =−3.2985 + 0.009 T b
                                                                  ing K W = 12 (or F = 0) and for low-boiling fractions value
                                       (T b > 478 K)
            F =−3.2985 + 0.009 T b
                                                                  of normal boiling point, T b , can be used instead of T in Eq.

                                                                                                             b
                                                                  (3.31). To use these equations for the conversion of boiling
            where                                                 point from one low pressure to another low pressure (i.e.,
                P = pressure at which boiling point or distillation data  from 1 to 10 mm Hg), two steps are required. In the first step,
                    is available, mm Hg                           normal boiling point or T (760 mm Hg) is calculated from
                T = boiling point originally available at pressure P,in  T (1 mm Hg) by Eq. (3.29) and in the second step T (10
                    kelvin                                        mm Hg) is calculated from T (760 mm Hg) or T b through Eqs.
                T = normal boiling point corrected to K W = 12, in

                 b                                                (3.30) and (3.31).
                    kelvin                                         In the mid 1950s, another graphical correlations for the
                T b = normal boiling point, in kelvin             estimation of vapor pressure of high boiling hydrocarbons
               K W = Watson (UOP) characterization factor [ = (1.8T b ) 1/3  were proposed by Myers and Fenske [28]. Later two simple
                    /SG]                                          linear relations were derived from these charts to estimate
                F = correction factor for the fractions with K W different  T (10 mm Hg) from the normal boiling point (T b ) or boiling
                    from 12                                       point at 1 mm Hg as follows [29]:
              log 10  = common logarithm (base 10)
                                                                  T(10 mm Hg) = 0.8547T(760 mm Hg) − 57.7 500 K < T(760 mm) < 800K
            The original evaluation of this equation is on prediction of va-  T(10 mm Hg) = 1.07T(1 mm Hg) + 19  300 K < T(1 mm) < 600K
            por pressure of pure hydrocarbons. Reliability of this method
            for normal boiling point of petroleum fractions is unknown.  (3.32)
            When this equation is applied to petroleum fractions, gener-  where all temperatures are in kelvin. These equations repro-
            ally K W is not known. For these situations, T is calculated  duce the original figures within 1%; however, they should

                                                  b
            with the assumption that K W is 12 and T b = T . This is to  be used within the temperatures ranges specified. Equa-

                                                    b
            equivalent to the assumption of F = 0 for low-boiling-point  tions (3.30) and (3.31) are more accurate than Eq. (3.32) but
            compounds or fractions. To improve the result a second round  for quick hand estimates the latter is more convenient. An-
            of calculations can be made with K W calculated from esti-  other simple relation for quick conversion of boiling point at
            mated value of T . When this equation is applied to distilla-  various pressures is through the following correction, which

                          b
            tion curves of crude oils it should be realized that value of  was proposed by Van Kranen and Van Nes, as given by Van
            K W may change along the distillation curve as both T b and  Nes and Van Westen [30].
            specific gravity change.                                                              T b − 41  1393 − T
              Equation (3.29) can be easily used in its reverse form to  log 10  P T = 3.2041 1 − 0.998 ×  ×
            calculate boiling points (T) at low or elevated pressures from                       T − 41  1393 − T b
            normal boiling point (T b ) as follows:               (3.33)
                                                                  where T is the boiling point at pressure P T and T b is the normal
                                      T
            (3.30)  T =                b                          boiling point. P T is in bar and T and T b are in K. Accuracy of
                        748.1Q − T (0.3861Q − 0.00051606)         this equation is about 1%.

                                 b
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