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856    Answers to Selected Problems

                        with
                                                 4ω sin(4ω) + cos(4ω) − 1  sin(4ω) − 4ω cos(4ω)
                                             a ω =                  ,b ω =
                                                        πω  2                  πω  2
                        By Fourier transform,
                                                               1      4
                                                      u(x,t) = √     ξe −(x−ξ) 2 /4kt  dξ
                                                             2 πkt  0

                                       ω
                                  ∞          −ω 2 kt
                                2
                      5. u(x,t) =           e    dω
                               π  0  α + ω 2
                                      2

                                     1 − cos(hω)
                                2    ∞                −ω 2 kt
                      7. u(x,t) =  0            sin(ωx)e  dω
                               π         ω
                                       ω
                                  ∞               −ω 2 t −t 2 /2
                                4
                      9. u(x,t) =          sin(ωx)e  e   dω
                                         2 2
                               π  0  (1 + ω )
                     Section 17.4 Laplace Transform Techniques
                                           (2n + 1)L − x      (2n + 1)L + x


                                   ∞
                      1. u(x,t) = T 0  erfc    √       − erfc     √
                                   n=0
                                              2 kt               2 kt
                                             √                x
                                                          kt

                                     kt
                      3. u(x,t) = e kt−x  − e ∗ L −1  e − s/kx  = e kt−x  − e ∗ √  e −x 2 /4kt
                                                            2 πt 3
                     Section 17.5 Heat Conduction in an Infinite Cylinder
                      1. Write
                                                      ∞            1
                                                           2
                                                                                    − j 2
                                                                    2
                                              U(r,t) =             ξ J 0 ( j n ξ)dξ  J 0 ( j n r)e  n t.
                                                        [J 1 ( j n )] 2
                                                      n=1        0
                        Inserting the approximate values, we have
                                            U(r,t) ≈0.8170J 0 (2.405r)e −5.785t  − 1.1394J 0 (5/520r)e −30.47t
                                                   + 0.7983J 0 (8.654r)e −74.89t  − 0.747J 0 (11.792r)e −139.04t
                                                   + 0.6315J 0 (14.931r)e −222.93t .
                      3.
                                                  ∞            1
                                                       2

                                                                     2
                                                                                        n
                                          U(r,t) =             ξ(9 − ξ )J 0 ( j n ξ)dξ  J 0 ( j n r/3)e  − j 2 t/18
                                                    (J 1 ( j n )) 2
                                                  n=1        0
                        The fifth partial sum approximation is
                                        U(r,t) ≈9.9722J 0 (2.405r/3)e −5.78t/18  − 1.258J 0 (5.520r/3)e −30.47t/18
                                               + 0.4093J 0 (8.654r/3)e −74.89t/18  − 0.1889J 0 (11.792r/3)e −139.04t/18
                                               + 0.1048J 0 (14.931r/3)e  −222.93t/18
                     Section 17.6 Heat Conduction in a Rectangular Plate
                      1.
                                                        ∞  ∞

                                               u(x,t,t) =    b nm sin(nπx/L)sin(mπy/K)e −β nm kt
                                                       n=1 n=1
                        where
                                                                 n   m
                                                                  2   2
                                                           β nm =  +     π  2
                                                                 L 2  K  2
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                                   October 14, 2010  17:50  THM/NEIL    Page-856        27410_25_Ans_p801-866
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