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Section 8-2/Conidence Interval on the Mean of a Normal Distribution, Variance Known     283


                                            Suppose that the population of interest has a normal distribution with unknown mean μ and
                                         unknown variance σ . Assume that a random sample of size n, say, X , X , …, X , is available,
                                                          2
                                                                                                1  2     n
                                         and let X and S  be the sample mean and variance, respectively.
                                                     2
                                            We wish to construct a two-sided CI on μ. If the variance σ 2  is known, we know that
                                                    σ
                                                                                             2
                                         Z = ( X − μ) /( /  n) has a standard normal distribution. When σ  is unknown, a logical pro-
                                         cedure is to replace σ  with the sample standard deviation S. The random variable Z  now
                                         becomes T = ( X − μ) /( S  n). A logical question is what effect replacing σ with S has on the
                                         distribution of the random variable T. If n is large, the answer to this question is “very little,”
                                         and we can proceed to use the conidence interval based on the normal distribution from Sec-
                                         tion 8-1.5. However, n is usually small in most engineering problems, and in this situation, a
                                         different distribution must be employed to construct the CI.

                     8-2.1  t DISTRIBUTION


                              t Distribution
                                             Let X , X , … , X  be a random sample from a normal distribution with unknown mean
                                                 1  2    n
                                                                  2
                                             μ and unknown variance σ . The random variable
                                                                             X − μ
                                                                         T =                               (8-13)
                                                                            S / n
                                             has a t distribution with n – 1 degrees of freedom.



                                         The t probability density function is

                                                               Γ[( k + )1 2 ]    1
                                                          f x ( ) =      ⋅          (      −∞ < x < ∞          (8-14)
                                                                                      /
                                                                     k ) ⎡
                                                                  k π Γ( 2  (  2   ⎤  k+ ) 1 2
                                                                          ⎣  x k) +1 ⎦
                                         where k is the number of degrees of freedom. The mean and variance of the t distribution are
                                                   k
                                         zero and k ( − 2 ) (for k > 2), respectively.
                                            Several t distributions are shown in Fig. 8-4. The general appearance of the t distribution
                                         is similar to the standard normal distribution in that both distributions are symmetric and uni-
                                         modal, and the maximum ordinate value is reached when the mean μ = 0. However, the t dis-
                                         tribution has heavier tails than the normal; that is, it has more probability in the tails than does
                                         the normal distribution. As the number of degrees of freedom k → ∞, the limiting form of the
                                         t distribution is the standard normal distribution. Generally, the number of degrees of freedom
                                         for t is the number of degrees of freedom associated with the estimated standard deviation.
                                            Appendix Table V provides percentage points of the t distribution. We will let t  be the
                                                                                                             α,k
                                         value of the random variable T with k degrees of freedom above which we ind an area (or
                                         probability) α. Thus, t  is an upper-tailed 100α percentage point of the t distribution with k
                                                           α,k
                                         degrees of freedom. This percentage point is shown in Fig. 8-5. In the Appendix Table V, the
                                         α values are the column headings, and the degrees of freedom are listed in the left column. To
                                         illustrate the use of the table, note that the t-value with 10 degrees of freedom having an area
                                         of 0.05 to the right is t  = 1.812. That is,
                                                           0.05,10
                                                                  10 (  , ) = (            .
                                                                            P T >1 812.
                                                               P T > t 0 05 10.  10    ) =  0 05
                                         Because the t distribution is symmetric about zero, we have t   = –t ; that is, the t-value
                                                                                           1–α,n  α,n
                                         having an area of 1 – α to the right (and therefore an area of a to the left) is equal to the nega-
                                         tive of the t-value that has area a in the right tail of the distribution. Therefore, t   = –t   =
                                                                                                        0.95,10  0.05,10
                                         –1.812. Finally, because t ,α ∞  is the standard normal distribution, the familiar z  values appear
                                                                                                       α
                                         in the last row of Appendix Table V.
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