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94 3 Estimating Data Parameters
The deviation of this formula from the exact formula is negligible for large n
(see e.g. Spiegel MR, Schiller J, Srinivasan RA, 2000, for details).
One can also assume a worst case situation for σ, corresponding to p = q = ½
⇒ σ = 2 ( ) n − 1 . The approximate 95% confidence level is now easy to remember:
±
ˆ
p 1 / n .
Also, note that if we decrease the tolerance while maintaining n, the confidence
level decreases as already mentioned in Chapter 1 and shown in Figure 1.6.
Example 3.5
Q: Consider, for the Fres hmen dataset, the estimation of the proportion of
freshmen that are displaced from their home (variable DISPL). Compute the 95%
confidence interval of this proportion.
A: There are n = 132 cases, 37 of which are displaced, i.e., p ˆ = 0.28. Applying
formula 3.15, we have:
p ˆ − 1.96 p / ˆˆ q n < p < p ˆ + 1.96 p / ˆˆ q n ⇒ 0.20 < p < 0.36.
Note that this confidence interval is quite large. The following example will
give some hint as to when we start obtaining reasonably useful confidence
intervals.
Example 3.6
Q: Consider the interval estimation of a proportion in the same conditions as the
previous example, i.e., with estimated proportion p ˆ = 0.28 and α = 5%. How large
should the sample size be for the confidence interval endpoints deviating less than
ε = 2%?
A: In general, we must apply the following condition:
z 1−α 2 / p ˆ ˆq ≤ ε ⇒ n ≥ z 1−α 2 / p q ˆ ˆ 2 . 3.17
n ε
In the present case, we must have n > 1628. As with the estimation of a mean, n
grows with the square of 1/ε. As a matter of fact, assuming the worst case situation
for σ, as we did above, the following approximate formula for 95% confidence
level holds: >n ~ / 1 ( ) ε 2 .
Confidence intervals for proportions, and lower bounds on n achieving a desired
deviation in proportion estimation, can be computed with Tools.xls .
Interval estimation of a proportion can be carried out with SPSS, STATISTICA,
MATLAB and R in the same way as we did with means. The only preliminary step