Page 194 - Arrow Pushing in Inorganic Chemistry A Logical Approach to the Chemistry of the Main Group Elements
P. 194

THE HEAVIER PNICTOGENS
                174
                So we now have a pentavalent P with three hydrogens and two O ligands. A second hydride
                transfer seems necessary to kick out one of the oxygens:
                      H
                   H                                      −
                      P   O      −           H          O                         −
                   H         +  O                  O  P              H     O  +  O
                      O     P   OH          H   P         OH            P     P   OH
                   H                        H      O  +             H
                          H                            H
                                                                      H   H   OH
                                                   H
                                                                                 (5B.34)
                Deprotonation of the PH group (note that we have reoriented the molecule a bit below) and
                                   4
                simultaneous departure of phosphate—effectively a reductive elimination—now accounts
                for the observed products. Below we have shown an intramolecular path for the process,
                but an external base could also have accomplished the deprotonation:

                                H                        H      −      OH
                             H      O      OH                 +  O      OH
                                 P      P   OH             P        P  +
                             H           +              H                        (5B.35)
                                 H     O                 H          OH
                                       −




                  REVIEW PROBLEM 5B.12
                  Consider reaction (5B.32):

                                        3H PO → PH + 2H PO    3
                                                           3
                                           3
                                                     3
                                              2
                  where three molecules of hypophosphorous acid come together and redistribute their
                  ligands on phosphorus. Suggest a mechanism.
                    Hint: This is clearly a somewhat complex problem. One solution we have thought
                  of involves an intermediate where three hypophosphorous acid molecules have linked
                  up together, as follows.
                                                                   OH
                                      −      HO            −   O   P +
                                      O  +  H   +          O    H
                                        P    −  P  H          P      H
                                             O             HO   H
                                      HO H     H              H
                                                         HO                   HO
                                  −                    −     +                    H
                              H                             P  H
                           O      O                   O                     O   P  OH
                                     +                   H
                    −  O   P +      P  H       −  O   P +  HO                   H
                   O                          O                      −   O  P  +
                        H        H                 H                O
                      P      H    HO             P      H                H    H
                   HO    H                    HO    H                  P
                      H                          H                  HO    H
                                                                       H
                  The stage is now set for hydride transfers.
   189   190   191   192   193   194   195   196   197   198   199