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          134                      CAM DESIGN HANDBOOK

                3

                               [w] :   [T] 1         [w] :   [T] 2
                                                       1
                                 1
                               [w] :   [T] 1         [w] :   [T] 2
                                                       2
                                 2






             Velocity  1

















               –1
                  0                           .5                          1
                                        Normalized time
            FIGURE 5.21.  Comparison of cam-follower velocities in Example 7.



             An alternative is to find a numerical procedure that will approximate the solution to
          Eq. (5.22), subject to the boundary conditions from the output motion. These boundary
          conditions result from the ten conditions listed earlier plus any additional ones that come
          from the applications. By considering the original ten constraints, the following conditions
          on the cam motion are obtained:
                    S ()+(  K C (wb   )) S 0 () =  0
                      1 ()
                        0
                             f
                                        c
                                f
                     c
                                   d
                                         1 ( )
                                           0
                    S c  2 ()  0 ()+( K C (wb )) S () =  0
                             f
                                    d
                                f
                                        c
                    S ()+(  K C (wb   )) S c  2 ( )  0 () =  0
                      3 ()
                        0
                                f
                     c
                                    d
                             f
                    S ()+( K C (wb    )) S 1 () = () (  K )  h C (wb )
                      1 ()
                                               h K +
                                            S 1
                       1
                     c      f  f   d    c         s   f  c  f  d
                      2 ()               1 ( )
                                          1
                    S   1 ()+( K C (wb )) S () =  0
                     c       f  f  d    c
                    S ()+( K C (wb    )) S c  2 ( )  1 () =  0.         (5.23)
                      3 ()
                        1
                                   d
                                f
                             f
                     c
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