Page 102 - Corrosion Engineering Principles and Practice
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76   C h a p t e r   4                           C o r r o s i o n   T h e r m o d y n a m i c s    77


                      be considered, that is, two solid species (Al and Al O ·H O) and two
                                                                     2
                                                                 2
                                                                   3
                                     3+
                      ionic  species  (Al   and  AlO ).  The  first  equilibrium  to  consider
                                               −
                                               2
                      examines the possible presence of either Al  or AlO  expressed in
                                                                    −
                                                           3+
                                                                   2
                      Eq. (4.42).
                                     Al 3+ +  2H O   AlO 2 −  +  4H       (4.42)
                                                            +
                                             2
                         Since there is no change in valence of the aluminum present in the
                      two ionic species considered, the associated equilibrium is independent
                      of the potential and the expression of that equilibrium can be derived in
                      Eq. (4.43) for standard conditions.
                                     RT ln  K eq  =  RT ln Q = −∆ G reaction     (4.43)
                                                         0
                      where Q is expressed in Eq. (4.44).
                                              a    × a 4
                                           Q =  AlO 2 −  H +               (4.44)
                                              a  + ×  a 2
                                               Al 3  H O
                                                      2
                         Assuming that the activity of H O is unity and that the activities
                                                    2
                      of the two ionic species are equal, one can obtain a simpler expression
                                                                              +
                      of the equilibrium in Eq. (4.43) based purely on the activity of H ,
                      Eq. (4.45) and its logarithmic form, Eq. (4.46).
                                        RT ln [H ] = −∆ G 0 reaction       (4.45)
                                               +
                                                4
                                                        0
                                   log 10  [H ] = − pH =  4 ×  −G reaction  RT     (4.46)
                                          +
                                                      2.303 ×
                             0
                      and if G  is expressed in joules and the temperature is 25°C or 298 K
                      Eq. (4.46) is even further simplified in Eq. (4.47).
                                       pH =  4.38 ×  10 −5  × G 0 reaction    (4.47)
                         By using the standard thermodynamic data from the literature [3],
                      it  is  possible  to  calculate  that  the  free  energy  of  reaction  in
                                                                    3+
                                                       −1
                      Eq. (4.42) is in fact equal to 120.44 kJ mol  when both [Al ] and [AlO ]
                                                                              −
                                                                              2
                      are equal. Equation (4.47) then becomes Eq. (4.48).
                                   pH =  4.38 ×  10 −5  ×  120,440 =  5.27    (4.48)
                         This is represented, in the E-pH diagram shown in Fig. 4.11, by
                                                                            3+
                      a dotted vertical line separating the dominant presence of Al  at
                      low pH from the dominant presence of AlO  at the higher end of
                                                             −
                                                            2
                      the pH scale.
                         The next phase for constructing the aluminum E-pH diagram is
                      to consider all possible reactions between the four chemical species
                      containing aluminum retained for this exercise, that is, Al, Al O ·H O,
                                                                        2
                                                                             2
                                                                          3
                      Al ,  and  AlO .  These  reactions  are  summarized  in  Table  4.12.  A
                        3+
                                   −
                                  2
                      computer program that would compare all possible interactions and
                      rank the chemical species involved in terms of their thermodynamic
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