Page 107 - Corrosion Engineering Principles and Practice
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82    C h a p t e r   4                                                                                                   C o r r o s i o n   T h e r m o d y n a m i c s    83



                       Equilibria
                          −
                       2 e  + 2H  = 1H
                               +
                                    2
                                    +
                       4 e  + 1O  + 4H  = 2H O
                          −
                               2         2
                       2 e  + 1Fe(OH)  + 2H  = 1Fe + 2H O
                          −
                                        +
                                   2              2
                       2 e  + 1Fe  = 1Fe
                                2+
                          −
                          −
                                    −
                       2 e  + 1Fe(OH)  + 3H  = 1Fe + 3H O
                                         +
                                   3               2
                          −
                                        +
                       1 e  + 1Fe(OH)  + 1H  = 1Fe(OH)  + 1H O
                                   3             2    2
                       1 e  + 1Fe(OH)  + 3H  = 1Fe  + 3H O
                                        +
                          −
                                              2+
                                   3                2
                       1Fe(OH)  + 1H  = 1Fe(OH)  + 1H O
                                   +
                              −
                              3              2    2
                       1 e  + 1Fe(OH)  = 1Fe(OH)  −
                          −
                                   3        3
                       1Fe  + 3H O = 1Fe(OH)  + 3H +
                          3+
                                2         3
                       1Fe  + 2H O = 1Fe(OH)  + 2H +
                          2+
                                2         2
                          −
                                3+
                       1 e  + 1Fe  = 1Fe 2+
                          2+
                                         +
                       1Fe  + 1H O = 1FeOH  + 1H +
                                2
                       1FeOH  + 1H O = 1Fe(OH)   + 1H +
                             +
                                  2         2(sln)
                       1Fe(OH)   + 1H O = 1Fe(OH)  + 1H +
                                                −
                              2(sln)  2        3
                       1Fe  + 1H O = 1FeOH  + 1H +
                                         2+
                          3+
                                2
                             2+
                       1FeOH  + 1H O = 1Fe(OH)  + 1H +
                                             +
                                  2          2
                       1Fe(OH)  + 1H O = 1Fe(OH)   + 1H +
                              +
                              2    2          3(sln)
                       1FeOH  + 1H  = 1Fe  + 1H O
                                        2+
                                  +
                             2+
                                              2
                                              2+
                                    +
                       1 e  + 1Fe(OH)  + 2H  = 1Fe  + 2H O
                                         +
                          −
                                   2                2
                       1 e  + 1Fe(OH)   + 1H  = 1Fe(OH)   + 1H O
                          −
                                          +
                                   3(sln)          2(sln)  2
                       1 e  + 1Fe(OH)   + 2H  = 1FeOH  + 2H O
                                          +
                          −
                                                  +
                                   3(sln)              2
                          −
                       1 e  + 1Fe(OH)   + 3H  = 1Fe  + 3H O
                                                2+
                                          +
                                   3(sln)             2
                      TABLE 4.13  Possible Reactions in the Fe-H O System between the Species
                                                       2
                      Most Stable in Wet Conditions
                      produces  ferric  ions  (Fe   or  Fe  III),  ferric  hydroxide  [Fe(OH) ],
                                            3+
                                                                              3
                      ferrous  hydroxide  [Fe(OH) ],  and  at  very  alkaline  conditions,
                                               2
                                    −
                      complex  HFeO   ions.  In  Fig.  4.16,  the  solid  corrosion  products
                                   2
                      considered  are  ferric  oxide  (Fe O )  and  magnetite  (Fe O ),  both
                                                                         4
                                                  2
                                                    3
                                                                       3
                      important iron ore constituents.
                         The presence of a relatively large immunity region in Fig. 4.15
                      and  Fig.  4.16,  where  corrosion  products  are  solid  and  possibly
                      protective,  indicates  that  iron  may  corrode  much  less  under  these
                      potential/ pH conditions.
                         These diagrams also indicate that if the potential of iron is made
                      sufficiently  negative  or  shifted  cathodically  below  approximately
                      −0.5 V vs. SHE in neutral or acidic environments, as indicated in
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