Page 148 - Design of Reinforced Masonry Structures
P. 148

4.12                       CHAPTER FOUR

             From the strain distribution diagram, using Eq. (4.15):
                             −
                                         5
                         ε =  dc  ε (  ) =  34  − .71 (.0025 ) = .0124
                                             0
                                                     0
                           s  c   mu    . 571
           It is noted that a strain of 0.0124 in the tension reinforcement is considerably larger than
           the yield strain value of 0.002 for Grade 60 reinforcement (therefore, the reinforcement
           is assumed to have yielded). The ratio of actual strain to yield strain is
                                   ε  0 0124
                                       .
                                     s  =   = 62
                                              .
                                   ε   0 002
                                        .
                                    y
             The strain in tension reinforcement is 6.2 times its yield strain value.
         4.5.2  Conditions for Yielding of Tension Reinforcement Based on
         Strain Compatibility

         4.5.2.1  Conditions for  Yielding of Tension Reinforcement in Beams at Balanced
         Conditions Fundamental relationships for yielding of steel reinforcement can be derived
         from compatibility of strains in a reinforced masonry beam. Figure 4.4 shows strain dis-
         tribution across in a reinforced masonry beam at the balanced conditions. Under these
         conditions, the ultimate strain in masonry is assumed to be equal to e  and the strain in the
                                                         mu
         tension reinforcement is assumed to be equal to the yield strain e .
                                                       y
           From similar triangles of the strain distribution diagram, we observe that
                                     c   ε
                                      =   mu                         (4.17)
                                     d  ε  + ε
                                         mu  y
         The value of c/d ratio that would result in yielding of tension reinforcement can be obtained
         from Eq. (4.17) by substituting appropriate values of the ultimate strains in masonry and
         reinforcement.
         a. Concrete masonry: Substitution of e  = 0.0025 for concrete masonry and e  = 0.002 for
                                     mu
                                                                y
           Grade 60 reinforcement in Eq. (4.17) yields
                           c    ε        0 0025
                                          .
                            =    mu  =            = 0 555            (4.18)
                                                    .
                                       .
                           d  ε mu  + ε y  0 0025  + 0 0020
                                             .
           Equation (4.18) shows that in a concrete masonry beam, Grade 60 reinforcement would

           yield when the condition given by Eq. 4.19 is satisfied:
                                      c
                                       ≤ 0 555                       (4.19)
                                         .
                                      d
           For all values of c/d > 0.555, the strain in steel would be less than the yield strain of
           0.002.
           An expression similar to Eq. (4.19) can be derived for Grade 40 reinforcement for which
           the yield strain is
                                   f    40
                               ε =  y  =    = 0 00138                (4.20)
                                              .
                                y
                                        ,
                                  E s  29 000
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