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0593_C15_fm  Page 518  Tuesday, May 7, 2002  7:05 AM





                       518                                                 Dynamics of Mechanical Systems



                                                                       Y
                                                                          n
                                                                           2
                                                                B
                                                                          P

                                                                                           X
                                                                         G
                                                                                        n  1
                                                                        ˆ
                                                                        P
                       FIGURE 15.4.3
                                                                   n  3
                       An arbitrarily shaped body  B with
                                        ˆ
                       particle weights P and .              Z
                                        P
                                                                  *
                       Then, by substituting into Eq. (15.4.5), we find T  to be:
                                                T =−Ω  2    I  n + I  n + I  n )
                                                 *
                                                        n ×( 11 1
                                                         1        12  2  13  3
                                                                                               (15.4.7)
                                                   =−I  Ω 2 n + I  Ω 2 n
                                                      12   3  13   2
                       Observe that the product of inertia terms I  and I  cause the body B to have inertia force
                                                            12
                                                                   13
                       moments perpendicular to the axis of rotation and thus be out of balance. Hence, the product
                       of inertia terms are a measure of the imbalance. Knowing this, we can bring the body into
                       balance by judiciously adding weights that will reduce the product of inertia terms to zero.
                        To explore these concepts, suppose an arbitrarily shaped body B has an inertia dyadic
                       as in Eq. (15.4.6) whose scalar components  I B  relative to n  and n  have the matrix form:
                                                              ij           i     j
                                                          I   B  I  B  I 
                                                                     B
                                                                     B 
                                                           11  12   13
                                                     I =  I  B  I  B  I                        (15.4.8)
                                                      B
                                                      ij   21  22   23 
                                                          I   B  I  B  I 
                                                                     B
                                                          31   32   33 
                       Suppose further that the product of inertia terms I , I , and I  are small compared with
                                                                       23
                                                                              31
                                                                    12
                       the moments of inertia terms I , I , and I . To see how we can balance the body by adding
                                                 11
                                                    22
                                                           33
                       weights, let the body and the weights be as depicted in Figure 15.4.3, where B, as before,
                                            ˆ
                                           P
                       is the body and P and   are particle weights, each having mass m.
                        Specifically, let X, Y, and Z be mutually perpendicular axes fixed in B with origin at the
                       mass center G  of  B. Let P  and  P ˆ   be placed at opposite ends of a line segment whose
                       midpoint is at G (see Figure 15.4.3). Finally, let n , n , and n  be mutually perpendicular
                                                                  1
                                                                            3
                                                                     2
                       unit vectors parallel to X, Y, and Z.
                                                                                   ˆ
                        It is readily seen that the n , n  inertia dyadic components of P and   are (see Eq. (7.3.11)):
                                                                                  P
                                               i
                                                  j
                                                    ( y + )   − xy      − xz  
                                                      2
                                                         2
                                                        z
                                              I =  m    − xy  ( x + )  − yz                (15.4.9)
                                                               2
                                              P
                                                                   2
                                                                  z
                                              ij
                                                     −        −       ( x + ) 
                                                                             2
                                                                         2
                                                      xz        yz         y  
                       and
                                                    ( y ˆ + )  − xy ˆ ˆ  − xz ˆˆ  
                                                         2
                                                      2
                                                        z ˆ
                                              I =  m    − xy ˆ ˆ  ( x ˆ + )  − yz ˆˆ      (15.4.10)
                                              P ˆ
                                                               2
                                                                  z ˆ
                                                                   2
                                              ij
                                                                            y ˆ 
                                                     −        −       ( x ˆ + )
                                                                         2
                                                                             2
                                                      xz ˆˆ     yz ˆˆ        
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