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                                             9.6 Uniform Asymptotic Approximations           283

                        for some 	> 0 and, hence,
                                               √   √

                                       ∞
                                         exp(x) nφ( nx) dx
                                       z n                          −1
                                        √            √     = 1 + O(n )as n →∞.
                                      φ( nz n )exp(z n )/( nz n )
                          However,
                                                               √
                               √             √           exp(z 0 / n)     1          1
                             φ( nz n )exp(z n )/( nz n ) = φ(z 0 )  = φ(z 0 )  1 + O √    .
                                                             z 0          z 0         n
                        The exact value of the integral in this case is
                                                                                    1
                                                      √                     1
                                exp{1/(2n)}[1 −  (z 0 − 1/ n)] = 1 −  (z 0 ) + φ(z 0 )√ + O  .
                                                                             n      n
                        Hence, if the approximation is valid to the order stated, then
                                                            1          1
                                            1 −  (z 0 ) = φ(z 0 )  1 + O n −  2  ,
                                                            z 0
                        that is,
                                                                   1
                                                   1 −  (z 0 ) = φ(z 0 )  .
                                                                  z 0
                        It follows that (9.3) is guaranteed to hold only valid for fixed values of z.

                          In this section, we present a asymptotic approximation to integrals of the form

                                                    ∞
                                                          √   √
                                                      h(x) nφ( nx) dx                       (9.4)
                                                   z
                        that overcomes both of the drawbacks illustrated in the previous example. Specifically,
                        this approximation has the properties that the form of the approximation does not depend
                        on the value of z and that the approximation is valid uniformly in z. The approximation
                        takes advantage of the fact that the properties of the integral (9.4) when h is a constant are
                        well-known; in that case,
                                           ∞

                                                 √   √                   √
                                             h(x) nφ( nx) dx = h(z)[1 −  ( nz)].
                                          z
                        Note that it is generally necessary to do a preliminary transformation to put a given integral
                        into the form (9.4).
                        Theorem 9.16. Consider an integral of the form
                                                    ∞

                                                          √    √
                                                      h n (x) nφ( nx) dx
                                                   z
                        where h 1 , h 2 ,... is a sequence of functions such that
                                               ( j)         
   2
                                           sup |h (x)|≤ c j exp d j x ,  j = 0, 1, 2
                                               n
                                            n
                        for some constants c 0 , c 1 , c 2 , d 0 , d 1 , d 2 .
                          Then, for all M < ∞,
                           ∞

                                 √    √               √               1      h n (z) − h n (0)  √
                             h n (x) nφ( nx) dx = [1 −  ( nz)] h n (0) + O  +   √       φ( nz),
                          z                                           n           nz
                        as n →∞, uniformly in z ≤ M.
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