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38                    Finite Element Modeling and Simulation with ANSYS Workbench



                  For the plane truss shown above,

                                    P = 1000 kN,     L = 1 m,  E = 210  GPa,
                                                2
                                    A = 60  × 10 −4  m for elements 1 and  2,
                                        .
                                    A = 62  × 10 −4 m 2  for element 3.

                  Determine the displacements and reaction forces.

                 Solution
                 We have an inclined roller at node 3, which needs special attention in the FE solution.
                 We first assemble the global FE equation for the truss.
                  Element 1:

                                                o
                                           θ= 90 , l  = 0, m  = 1


                                                    u 1  v 1  u 2  v 2
                                                     0   0  0  0 
                                                  4 
                                         9
                                           60 ×
                                                 −
                                  ( 210 ×  10 )(.  10 )   0  1  0  − 1   
                               1 k =                               (N/m )
                                          1          0   0  0  0 
                                                       −         
                                                     0   1  0  1  
                  Element 2:
                                               o
                                           θ= 0 ,  l  = 1, m  = 0


                                                     u 2  v 2  u 3  v 3
                                                      1  0  − 1  0
                                                  4 
                                                  −
                                            60 ×
                                  ( 210 ×  10 )(.  10 )   0  0  0  0   
                                          9
                               2 k =                               (N/m )
                                           1         −   1  0  1  0
                                                                 
                                                       0  0  0  0  
                  Element 3:
                                                    1       1
                                              o
                                         θ= 45 , l  =  , m  =
                                                    2        2

                                                  u 1   v 1   u 3   v 3
                                                   05  05   − 05  − 05
                                                   .
                                                               .
                                                                     .
                                                         .
                                               4 
                                              −
                                                         .
                                                               .
                                                   .
                                                                     .
                                     9
                              ( 210 ×  10 )( 62 ×  10 )    05  05  − 05  − 05  
                           3 k =                                        (N/m )
                                                                    .
                                       2         − −  05.  −05.  05  05  
                                                              .
                                                                     
                                                                    .
                                                              .
                                                  −  05.  −05.  05  05   
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