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268                            Fundamentals of Water Treatment Unit Processes: Physical, Chemical, and Biological


              e.g., q(raw water) ¼ 1.0 s, as well as Q. With these
              assumptions, the calculated result, i.e., n ¼ 153 rev=s, is  BOX 10.6  MEASUREMENT
              too high from a practical standpoint, e.g., impeller power    OF IMPELLER TORQUE
              is proportional to n to the third power. A spreadsheet setup
              would be useful to examine the trade-offs, e.g., q(raw  For an experimental impeller mixing system, fabricated
              water) and thus D(impeller), Q(impeller)=Q(raw water),  by a machinist, the torque, T, imparted to an impeller
                                                    3
                                                      5
              and n. The use of the power number, P ¼ P=(rn D ) and  may be measured if the drive motor is mounted on a
              the plot for the Rushton system power number, P, provide  bearing plate (such as a ‘‘lazy susan’’ from a hardware
              a basis for estimating the power required for the system  store) above the basin. A lever rod is attached to the
              and thus the reasonableness of any design trials, e.g., for n
                                                                  motor and rotates with the motor; the motor as set up is
              and D(impeller). As noted, changes in the geometric pro-  free to rotate. A force gage is then mounted on the top of
              portions of the system, i.e., deviations from the Rushton
                                                                  the basin with a hook to restrain the lever rod (Figure
              design, result in changes to Q and P, which are not neces-
              sarily available in the literature.                 3.5). When an impeller is attached to the shaft from the
                                                                  motor, the associated force may be measured. The meas-
                                                                  ured force in Newtons (or lb) times the lever arm distance
            10.4.2.3.4  Power Dissipation                         in m (or ft) is the torque in N   m (lb   ft) generated by the
            The power transferred to an impeller is the product of the  motor to overcome the drag resistance of the impeller. If
            torque applied and its rotational velocity, i.e.,     a luminescent tape strip is attached to the shaft, its rota-
                                                                  tional velocity, n, may be measured by a strobe. Since
                                P ¼ T   v              (10:38)    n   2p ¼ v, the power, P, dissipated by the impeller is,
                                                                  P ¼ T   (n   2p). The power dissipated by friction may be
            where                                                 measured by removing the impeller and taking the same
              P is the power dissipated by the impeller (W)       measurements. Ordinarily, the measured friction torque
              T is the torque exerted by impeller due to fluid drag (N m)  should approach zero. To convert from kilograms-force
              v is the rotational velocity (rad=s)                to Newtons, N ¼ kg-force   9.80665; i.e., a kilogram of
                                                                  force (2.2 lb force) is that force exerted by gravity on a
                          v (rad=s) ¼ n (rev=s)   2p              mass of 1 kg.

              The experimental procedure to measure T and w is
                                                                  In other words, the energy dissipated as shear, i.e., turbu-
            described in Box 10.6.                                                                         2
                                                               lence, is proportional to the impeller speed squared, n , and
                                                                                              2
                                                               impeller diameter squared, D(impeller) .
            10.4.2.3.5  Shear
            The power imparted to the water by an impeller causes a  10.4.2.3.6  Shear=Flow Ratio
            pressure (head) increase if confined by a casing. In the  For most mixing situations, high shear (i.e., turbulence) is
            absence of a casing, the impeller energy is distributed between  required, along with some level of advection. To obtain an
            advection and turbulence, aggregated here as H(shear), since  expression for the shear-to-flow ratio, divide Equation 10.40
            the advective flow sheds eddies and ends up as turbulence.  by Equation 10.37 to give (Myers et al., 1999, p. 35),
            The power dissipated is thus (Myers et al., 1990, p. 35),

                                                                                                 n
                                                                             H(shear)     P
                         P ¼ Q(impeller)g H(shear)     (10:39)                        ¼
                                       w                                    Q(impeller)  gQ 2   D
                                                                                                          (10:41)

                                                                             H(shear)     P
                                                                                                 n
            where                                                                     ¼     2
                                                          3
              g w is the specific weight of water, i.e., g w ¼ r w g (N=m )  Q(impeller)  gQ     D
              H(shear) is the pseudo head due to impeller rotation dissi-
                pated as shear (m)                             Equation 10.41 shows that for a given system, i.e., for unique
                                                               values of P and Q, the shear-to-flow ratio is proportional to
                                                               the n=D ratio, i.e., higher values of n and smaller values of
              Equating the power terms of Equation 10.23, i.e., P ¼
               3  5                                            D(impeller). Illustrative values are (Myers et al., 1999, p. 36).
            P=(n D r), Section 10.3.3.1, and Equation 10.39, i.e., P ¼
            Q(impeller)g w H,  and  substituting  Equation  10.37,  Q
                         3
            (impeller)¼ QnD ,for Q, gives (Meyers et al., 1990, p. 35),
                                                                           Shear  Pumping  n (rpm)  D (m)
                                                                           High   Low     3500    0.1
                               P     2         2
                                     n D(impeller)     (10:40)             Low    High     100    1.0
                              Qg
                   H(shear) ¼
            where P is the power number for impeller–tank system  In other words, the distribution between shear and pumping
            (dimensionless).                                   flow may be controlled by the n=D ratio. Also, as seen, the
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