Page 284 - Handbook of Civil Engineering Calculations, Second Edition
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PRESTRESSED CONCRETE                  2.69

                              3. Determine whether the section moduli are excessive
                              Do this by setting f bf and f ti equal to their allowable values and computing the corresponding
                              values of f bi and f tf . Thus, f bf   0.85f bp   2334   425; therefore, f bp   2246 lb/sq.in.
                              ( 15,486.2 kPa); f ti   f tp   190 lb/sq.in. ( 1310.1 kPa);  f bi   f bp   2246 < 2400
                              lb/sq.in.( 16,548.0 kPa). This is acceptable. Also, f tf   0.85( 190)   1067   905 < 2250
                              lb/sq.in. ( 15,513.8 kPa); this is acceptable. The section moduli are therefore excessive.
                              4. Find the minimum prestressing
                              force and its eccentricity
                              Refer to Fig. 40. Thus,  f bp   2246
                              lb/sq.in. ( 15,486.2 kPa);  f tp   190
                              lb/sq.in. ( 1310.1 kPa); slope of AB
                              2246   ( 190)/16   152.3 lb/(sq.in.·in.)
                              (41.33 MPa/m); F i /A   CD   2246
                              10.98 (152.3)    574 lb/sq.in. (3957.7
                              kPa);  F i   574(316)    181,400 lb
                              (806,867.2 N); slope of  AB   F i e/I
                              152.3; e   152.3(7240)/181,400   6.07
                              in. (154.178 mm).
                              5. Determine the number of        FIGURE 40. Prestress diagram.
                              strands required, and establish
                              their disposition
                              In accordance with the ACI  Code, allowable initial force per strand    0.1089
                              (0.70)(248,000)   18,900 lb (84,067.2 N); number required   181,400/18,900   9.6.
                              Therefore, use 10 strands (5 in each web) stressed to 18,140 lb (80,686.7 N) each.
                                Referring to the ACI Code for the minimum clear distance between the strands, we
                                                                        3
                                                                 7
                              find the allowable center-to-center spacing   4( /16)   1 /4 in. (44.45 mm). Use a 2-in.
                              (50.8-mm) spacing. In Fig. 41, locate the centroid of the steel, or y   (2   2   1   4)/5
                              1.60 in. (40.64 mm); v   10.98   6.07   1.60   3.31 in. (84.074 mm); set v   3 /16 in.
                                                                                          5
                              (84.138 mm).
                              6. Calculate the allowable ultimate moment of the member
                              in accordance with the ACI Code
                                                                  2
                              Thus, A s   10(0.1089)   1.089 sq.in. (7.0262 cm ); d   y t   e   5.02   6.07   11.09
                              in. (281.686 mm); p   A s /(bd)   1.089/[72(11.09)]   0.00137.



















                                            FIGURE 41. Location of tendons.
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