Page 322 - Industrial Power Engineering and Applications Handbook
P. 322

Protection of electric motors  12/301
                                              instantaneous
                                              setting 850%
















                  TWO  consecutive/
                    hot starts
                           I, 100

                                          38 40
                                                        Time (seconds) +
                                     Figure 12.33  Plotting of  starting current and thermal curves


             Use a CT of  ratio 15011A.                     Step II: Selection of  HRC fuses
                                                            I,  = 123.2 A
             Note  If a power capacitor is connected after the relay, say
             across the motor terminals, to improve the p.f. of the machine,   I,,  = 750% of  1,
             then only  the corrected  value of the current must be used.
             For example, if a capacitor bank of  130 kVAr is used for an   Le. 924 A
             individual correction of the machine then      fs  = 19.0 seconds
                                   130
                             I,  =   I                      Consider four equally spread starts/hour. From the selection
                                 ~'3 2.64                   chart  in  Figure  12.34, select  the  characteristics  B-6 and
                                    x
                               = 28.43 A                    determine  the  fuse  rating  as  350  A  on  the  ordinate
                                                            corresponding to a starting current of 924 A on the abscissa.
             where,          /c  = capacitor current
             Since     at 0.85 p.f. = 123.2 A               Step 111:  Selection of  bimetallic overcurrent  relay
                                                            Consider the available setting range as
                        I,  (active) = 123.2 x 0 85
                                                            (a) Overcurrent: 80-125%
                               = 104.72 A                   (b) Instantaneous unit: 800-1 400%
             and      /r  (reactive) = 123.2 x 0.527
                                                            The thermal curve of the motor does not show any significant
                               = 64.9 A                     overload  capacity  and therefore  the  relay  must be  set  as
                Net reactive current = 64.9 - 28.43
             :_                                             close to the full-load current as possible, say at a setting of
                                                            11 0%. Then
                               = 36.47 A
                                                            Overcurrent relay tapping  = l.'   123.2 (relay rating: 1  A)
             and I,  (corrected) that the relay will detect                      1.05 x  150
                               =  b!(104.72' + 36.47')                         = 86% Of  1 A
                               = 110.9 A                    Note  The factor  1.05 (typical) is the pick-up current of the
                                                            relay.
             All further calculations  must be based on this current.
                                                            Say the relay is set at 85%. Then it will operate at 85/86 x 11 0,
                                                            i.e. at  108.7% of  I,,  which should be appropriate and the
                                                            instantaneous setting
                                   104.72A                       =  1.087 x  750 = 815.25%
                                                            say,   815%
                                                            This setting is only a calculation. The exact thermal curves of
                                                            the motor and the relay should be available to closely match
                                                            their characteristics at every point. An ideal relay in this case
                                          1
                           sin @ = 0 527                    would  be  one  which,  without  tripping,  will  permit  two
                                        64.9A               consecutive hot starts, i.e. its characteristic should fie above
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