Page 590 - 04. Subyek Engineering Materials - Manufacturing, Engineering and Technology SI 6th Edition - Serope Kalpakjian, Stephen Schmid (2009)
P. 590

Section 21.4  Temperatures in Cutting


                         TABLE 2 l.2
                          Approximate Range of Energy Requirements in Cutting
                          Operations at the Drive Motor of the Machine Tool
                          (for Dull Tools, Multiply by L25)
                                                            Specific energy
                         Material                            W S/mm3
                                                                °
                         Aluminum alloys                       0.4-1
                         Cast irons                            1.1-5.4
                         Copper alloys                         1.4-3.2
                         High-temperature alloys               3.2-8
                         Magnesium alloys                      0.3-0.6
                         Nickel alloys                         4.8-6.7
                         Refractory alloys                      3-9
                         Stainless steels                       2-5
                         Steels                                 2-9
                         Titanium alloys                        2-5
                                        10° and the width of F



                EXAMPLE 2|.l Relative Energies in Cutting

                In an orthogonal cutting operation, to = 0.13 mm,  and    /1"
                V =   120 m/min,  06 =
                cut = 6 mm. It is observed that tc = 0.23 mm,        R:   (13% +F§)=  2002 + 5002=539N
                PC = 500 N, and P, = 200 N. Calculate the percent-  Thus
                age of the total energy that goes into overcoming    ’
                friction at the tool-chip interface.                          500 1. 539 COS B, 10)
                                                                                           (
                Solution The percentage of the energy can be ex-  so
                pressed as                                                          B = 32°
                          Friction energy _ FV,  __ Fr           and
                           Total energy  T FCV _ FC’
                                                                             F = 539 sm 32° = 286 N
                where            to    013
                              V = Q; =  = 0-565,                 Hence,
                s___...__....r.,.r.. i>fl;...--...r..,...____..... ..,,,-,...-... .__.,.   _ss
                                                                  Percentage=  =0.32, or
                             F : Rsing,






              2|.4    Temperatures in Cutting


              As in all metalworking processes where plastic deformation is involved, the energy
              dissipated in cutting is converted into heat that, in turn, raises the temperature in the
              cutting zone. Temperature rise is a very important factor in machining because of its
              major adverse effects, such as the following:

                 ° Excessive temperature lowers the strength, hardness, stiffness, and wear resist-
                   ance of the cutting tool; tools also may soften and undergo plastic deforma-
                   tion; thus, tool shape is altered.
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