Page 180 - Marks Calculation for Machine Design
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P1: Shibu
                          January 4, 2005
                 Brown˙C04
        Brown.cls
                  162
                            U.S. Customary 14:25  STRENGTH OF MACHINES  SI/Metric
                      σ top = σ axial + σ max           σ top = σ axial + σ max
                         = (−0.25 kpsi) + (−2.0 kpsi)      = (−1.2MPa) + (−16.0MPa)
                         =−2.25 kpsi                       =−17.2MPa
                  Step 6. Display the answer for the maximum  Step 6. Display the answer for the maximum
                  normal stress at the top (σ top ) found in step 5,  normal stress at the top (σ top ) found in step 5,
                  in kpsi, on a uniaxial stress element.  in MPa, on a uniaxial stress element.
                                   0                                0
                            0                                0

                       2.25                2.25         17.2               17.2


                                       0                                 0
                                   0                                0
                    Negative signs are not used in the above di-  Negative signs are not used in the above di-
                  agram as the directions of the arrows indicate  agram as the directions of the arrows indicate
                  compression. As stated at the end of Example  compression. As stated at the end of Example
                  1, this diagram will be a starting point for the  1, this diagram will be a starting point for the
                  discussions in Chap. 5.            discussions in Chap. 5.

                  Location of Maximum Stress Elements.  The plane stress elements in Fig. 4.12 are for
                  two special locations in the cross section of the beam. As already mentioned, one part of
                  the normal stress (σ xx ) is constant and the other part varies over the cross section. The shear
                  stress (τ xy ) due to bending also varies over the cross section, but opposite to the normal stress
                  due to bending. Example 2 considered one of the two maximum stress elements, the element
                  at the top of the beam, whereas Example 3 will consider the element at the neutral axis. There
                  is actually a third stress element of interest, one at the bottom of the beam, where the normal
                  stress due to the axial load is still compressive but the normal stress due to bending is tensile.
                    In Fig. 4.13, the rectangular cross section of Example 1 is shown with the three darkened
                  rectangles locating these three special stress elements.

                                                   Top

                                Stress elements

                                                             Neutral axis





                                                       Bottom
                                FIGURE 4.13  Elements for maximum stress.
                    Consider the following example concerning the stress element at the neutral axis.
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