Page 221 - Marks Calculation for Machine Design
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P1: Shibu/Sanjay
                          January 4, 2005
                                      14:35
        Brown.cls
                 Brown˙C05
                                     PRINCIPAL STRESSES AND MOHR’S CIRCLE
                              U.S. Customary                      SI/Metric       203
                    and the minimum shear stress (τ min ) is  and the minimum shear stress (τ min ) is
                          τ min =−τ max =−7.5 kpsi           τ min =−τ max =−58 kpsi
                    Step 3. Using the average normal stress (σ avg )  Step 3. Using the average normal stress (σ avg )
                    found in step 1 and the maximum shear stress  found in step 1 and the maximum shear stress
                    (τ max ) found in step 2, calculate the maximum  (τ max ) found in step 2, calculate the maximum
                    principal stress (σ 1 ) from Eq. (5.15) as  principal stress (σ 1 ) from Eq. (5.15) as
                       σ 1 = σ avg + τ max = (3.5 + 7.5) kpsi  σ 1 = σ avg + τ max = (25 + 58) MPa
                         = 11 kpsi                          = 83 MPa
                    and use Eq. (5.16) to calculate the minimum  and use Eq. (5.16) to calculate the minimum
                    principal stress (σ 2 ) as         principal stress (σ 2 ) as
                       σ 2 = σ avg − τ max = (3.5 − 7.5) kpsi  σ 2 = σ avg − τ max = (25 − 58) MPa
                         =−4 kpsi                           =−33 MPa
                    Step 4. Before going further, check that the  Step 4. Before going further, check that the
                    values for the principal stresses (σ 1 ) and (σ 2 )  values for the principal stresses (σ 1 ) and (σ 2 )
                    satisfy Eq. (5.17)                 satisfy Eq. (5.17)
                             σ 1 + σ 2 = σ xx + σ yy           σ 1 + σ 2 = σ xx + σ yy
                       [11 + (−4)] kpsi = [10 + (−3)] kpsi  [83 + (−33)]MPa = [75 + (−25)]MPa
                              7 kpsi ≡ 7 kpsi                  50 MPa ≡ 50 MPa

                    and they do.                       and they do.
                    Step 5. Using Eq. (5.9), calculate the rotation  Step 5. Using Eq. (5.9), calculate the rotation
                    angle (φ p ) for maximum and minimum princi-  angle (φ p ) for maximum and minimum princi-
                    pal stresses as                    pal stresses as
                                  2τ xy                             2τ xy
                         tan 2φ p =                        tan 2φ p =
                                σ xx − σ yy                        σ xx − σ yy
                                  2 (−4 kpsi)                       2 (−30 MPa)
                              =                                  =
                                [10 − (−3)] kpsi                   [75 − (−25)]MPa
                                −8 kpsi                            −60 MPa
                         tan 2φ p =   =−0.615              tan 2φ p =    =−0.600
                                 13 kpsi                           100 MPa
                           2 φ p =−31.6 ◦                    2 φ p =−31.0 ◦
                            φ p =−15.8 ◦                      φ p =−15.5 ◦
                    Step 6. Without the benefit of the graphical  Step 6. Without the benefit of the graphical
                    picture of Mohr’s circle, the only way to tell  picture of Mohr’s circle, the only way to tell
                    which principal stress this value of the rotation  which principal stress this value of the rotation
                    angle (φ p ) is associated with is to substitute  angle (φ p ) is associated with is to substitute
                    this angle in Eq. (5.1) and see which stress is  this angle in Eq. (5.1) and see which stress is
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