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                                   Microhinges and Microcantilevers: Lumped-Parameter Modeling and Design

                              114   Chapter Three
                              Equation (3.21) reduces to Eq. (2.55) when l 1  = l 2  = l/2, w 2  = w 1  (con-
                              stant), and t 1  = t 2 , when the serial microcantilever of Fig. 3.7 becomes
                              a constant-cross-section member for the above-mentioned conditions.
                                In bending, it can be shown that the stiffness associated to the free
                              end 1 is calculated as

                                                             1
                                           k b,e  =  (1)  (2)  2 (2)    (2)              (3.22)
                                                 C   + C   + l C  +2l C
                                                  l     l    1  r    1 c
                              Equation (3.22) is verified, too, because when  l 1  =  l 2  =  l/2, w 2  =  w 1
                              (constant), and t  = t , it reduces to Eq. (2.61), which characterizes a
                                             1
                                                 2
                              constant  rectangular cross-section microcantilever  of length  l. The
                              lumped effective mass is
                                         {   l 1    1   2         l +l 2  (2)  2   }
                                                                  1
                                  m   = ȡ t 1ฒ w (x) f (x) dx + t 2 ฒ  w (x) f  (x)  dx  (3.23)
                                   b,e      0  1   b             l 1  2   b


                                     (1)
                                            (2)
                              where f b  and f b  are the bending-related distribution functions, which
                              are potentially different. Equation (2.66), which gives the effective iner-
                              tia of a constant-cross-section microcantilever of length l, is retrieved
                              from Eq. (3.23) when l 1  = l 2  = l/2, w 2  = w 1  (constant), and t 1  = t 2 .
                                In  the particular class  of micromembers formed  of two  compliant
                              segments, the two components are identical and placed in mirror, which
                              means the  resulting member has  a symmetry axis,  as  sketched  in
                              Fig. 3.7. Purposely, the member of this structure has no axial symmetry
                              about the x axis because this is not a prerequisite, although in the great
                              majority of practical situations, microhinges and microcantilevers do
                              also have axial symmetry. In  such cases,  the expression of bending
                              stiffness, which is expressed generically in Eq. (3.22), can be simplified.
                              The bending stiffness, which is calculated with respect to point 1 in
                              Fig. 3.7, can be formulated by first expressing the linear direct bending
                              compliance of the first (right-side) segment in terms of reversed
                              frames—the first of Eqs. (3.2), namely,
                                                                  2 (1)
                                                                  l C
                                                (1) Ҡ  (1)   (1)     r
                                              C    = C   í lC  +                         (3.24)
                                               l      l      c      4
                              and then applying the series-connection rule of Eq. (3.22). The bending
                              stiffness of the flexible member of Fig. 3.7 becomes
                                                             1
                                                k b,e  =  (2)                            (3.25)
                                                              2 (1)
                                                     2(C   + l C r / 4)
                                                         l



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