Page 127 - Modern Control Systems
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Section 2.8  Design  Examples                                       101

                       where  </>  =  tan  (<w/ft).  So, as t —> oo, we  have

                                          AQ 2 (0  ^     / ! 2  a  2  sm(<ot  -  ¢).
                                                       V f i  +  w
                       The maximum  change in output  flow rate  is

                                               lA^Olmax   =  - 7 = = 5 .                 (2.124)
                                                            V f i  2  +  a) 2
                           The  above  analytic  analysis  of the linear  system  model  to step and  sinusoidal
                       inputs is a valuable way to gain insight into the system response to test signals. An-
                       alytic  analysis  is limited, however,  in  the  sense  that  a more  complete  representa-
                       tion  can  be  obtained  with  carefully  constructed  numerical  investigations  using
                       computer  simulations  of  both  the  linear  and  nonlinear  mathematical  models.  A
                       computer  simulation  uses  a model  and  the  actual  conditions  of  the  system  being
                       modeled,  as well  as actual input  commands  to  which  the  system  will  be  subjected.
                          Various  levels  of simulation  fidelity  (that  is, accuracy)  are  available to the  con-
                       trol engineer. In the early stages of the design process, highly interactive design  soft-
                       ware packages are effective. At this stage, computer speed  is not as important  as the
                       time it takes to obtain an initial valid solution  and to iterate  and fine  tune that solu-
                       tion. Good  graphics output  capability  is crucial. The  analysis simulations  are  gener-
                       ally low fidelity  in the sense that  many  of the simplifications  (such  as  linearization)
                       made in the design process are retained  in the  simulation.
                          As the design matures usually it is necessary to conduct numerical  experiments
                       in  a more  realistic simulation  environment. At  this point  in  the  design  process, the
                       computer  processing  speed  becomes  more  important,  since  long  simulation  times
                       necessarily  reduce  the  number  of computer  experiments  that  can  be  obtained  and
                       correspondingly raise costs. Usually these high-fidelity  simulations are  programmed
                       in FORTRAN, C, C++, Matlab, Lab VIEW  or similar languages.
                          Assuming that  a model and the simulation are reliably accurate, computer  sim-
                       ulation has the following advantages [13]:

                          1.  System performance  can be observed under all conceivable conditions.
                          2. Results  of field-system  performance  can be extrapolated  with a simulation  model for
                            prediction purposes.
                          3.  Decisions concerning future  systems presently in a conceptual  stage can be examined.
                          4. Trials of systems under test can be accomplished  in a much-reduced  period  of time.
                          5.  Simulation results can be obtained  at lower cost than real  experimentation.
                          6.  Study of hypothetical situations can be achieved even when the hypothetical situation
                            would be unrealizable  at present.
                         7.  Computer modeling and simulation  is often  the only feasible or safe technique to
                            analyze and evaluate a system.
                          The nonlinear model describing the water level flow rate is as follows  (using the
                       constants given in Table 2.7):
                                                                        3
                                          H  =  -0.0443  V / 7  +  1.2732  X  10" Q b    (2.125)
                                            =  34.77Vtf.
                                         Q 2
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