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Section  3.4  Signal-Flow  Graph and Block Diagram Models            177
                          The block diagram model can also be constructed  directly from Equation (3.46).
                      Define  the intermediate variable Z{s) and rewrite Equation  (3.46) as

                                         = 1^1       V        2             Z{s)
                                    G(s)        =        + b 2s  + b lS  + b 0
                                           U(s)   S A  + a 3s 3  + a 2s 2  + a xs  + a 0  Z(s)'
                      Notice  that,  by  multiplying  by  Z(s)/Z(s),  we  do  not  change  the  transfer  function,
                      G(s). Equating the numerator and denominator polynomials yields
                                                     3
                                          Y(s)  =  [b 3s  + b 2s 2  + b iS  + b Q]Z(s)
                      and
                                                4
                                        U(s)  =  [s  + a 3s 3  + a 2s 2  + ais  + a Q]Z(s).
                      Taking  the  inverse  Laplace  transform  of  both  equations  yields  the  differential
                      equations
                                                 l
                                                          2
                                               ud z      d z     dz
                                           y  =  b  +  b 2  +  bl  +  b z
                                                 ^       ^      *     "
                      and
                                             4       3       2
                                            d z     d z     d z     dz
                                              4    3  3    2  2    l
                                            dt      dt     dt       dt
                      Define the four state variables as follows:
                                                    x x-z

                                                    X 2  =  X\  =  Z
                                                    x
                                                     3  —  X 2  —  Z
                                                            =
                                                    Xq  —  X 3  Z-
                      Then the differential  equation can be written equivalently as
                                                       xi  =  x 2,

                                                       X 2  =  X 3,
                                                      X3  =  X4,
                      and

                                         X\  =  Cl()X\  Cl\X 2  #2-^-3  ^3-^4  "^ Mi
                      and the corresponding output equation is

                                            y  =  b 0x {  + b xx 2  + b 2x 3  + b 3x 4.
                      The block diagram model can be readily obtained from the four first-order  differential
                      equations and the output equation as illustrated in Figure 3.11(b).
                          Furthermore, the output is simply

                                           y(t)  = b 0x x  + b xx 2  + b 2x 3 + b 3x 4.  (3.48)
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