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INTRODUCING HALF-CELLS AND ELECTRODE POTENTIALS      303

               The preferred electrolytes if the solvent is water are KCl and NaNO 3 . If the solvent
             is a non-aqueous organic liquid, then we prefer salts of tetra-alkyl ammonium, such
                                                    n
                                                          +
             as tetra-n-butylammonium tetrafluoroborate, Bu 4 N BF 4 .
                                                               −
     7.2     Introducing half-cells and electrode
             potentials



              Why are the voltages of watch and car batteries
              different?


             Relationships between emf and electrode potentials

             Being a cell, a battery contains two half-cells separated by an electrolyte. The elec-
             trodes are needed to connect the half-cells to an external circuit. Each electrode may
             act as part of a redox couple, but neither has to be.
               The market for batteries is huge, with new types and applications
             being developed all the time. For example, a watch battery is a type  An ‘electrode poten-
             of ‘silver oxide’ cell: silver in contact with silver oxide forms one  tial’ E is the energy
             half-cell while the other is zinc metal and dications. Conversely,  (expressed as a volt-
             a car battery is constructed with the two couples lead(IV)|lead  age) when a redox
             and lead(IV)|lead(II). The electrolyte is sulphuric acid, hence this  couple is at equilibrium.
             battery’s popular name of ‘lead–acid’ cell (see further discussion  The value of E cannot
                                                                          be measured directly
             on p. 347).                                                  and must be calculated
               The first difference between these two batteries is the voltage
                                                                          from an experimental
             they produce: a watch battery produces about 3 V and a lead–acid
                                                                          emf.
             cell about 2 V. The obvious cause of the difference in emf are
             the different half-cells. The ‘electrode potential’ E is the energy,
             expressed as a voltage, when a redox couple is at equilibrium.
                                                                          Two redox states of the
             As a cell comprises two half-cells, we can now define the emf
                                                                          same material form a
             according to                                                 redox couple.
                                                                  (7.22)
                        emf = E (positive half-cell) − E (negative half-cell)

               This definition is absolutely crucial. It does not matter if the
             values of E for both half-cells are negative or both are positive:
             E (positive) is defined as being the more positive of the two half-cells,  It is impossible to
                                                                          determine the potential
             and E (negative) is the more negative.
                                                                          of a single electrode:
               We now consider the emf in more detail, and start by saying  only its potential rel-
             that it represents the separation in potential between the two half-  ative to another elec-
             cell potentials; See Equation (7.22). In order for  G (cell) to remain  trode can be measured.
             positive for all thermodynamically spontaneous cell discharges, the
             emf is defined as always being positive.
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