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CHAP. 10]  LINE INTEGRALS, SURFACE INTEGRALS, AND INTEGRAL THEOREMS             243


                     INDEPENDENCE OF THE PATH
                     10.11. Let Pðx; yÞ and Qðx; yÞ be continuous and have continuous first partial derivatives at each point
                           of a simply connected region r.  Prove that a necessary and sufficient condition that
                           þ
                             Pdx þ Qdy ¼ 0 around every closed path C in r is that @P=@y ¼ @Q=@x identically in r.
                            C
                           Sufficiency.  Suppose @P=@y ¼ @Q=@x.  Then by Green’s theorem,
                                                               ðð
                                                  þ
                                                                  @Q  @P
                                                                         dx dy ¼ 0
                                                    Pdx þ Qdy ¼
                                                   C              @x  @y
                                                               r
                           where r is the region bounded by C.
                           Necessity.
                                     þ
                              Suppose  Pdx þ Qdy ¼ 0around every closed path C in r and that @P=@y 6¼ @Q=@x at some point of
                                     C
                           r.  In particular, suppose @P=@y   @Q=@x > 0atthe point ðx 0 ; y 0 Þ.
                              By hypothesis @P=@y and @Q=@x are continuous in r,sothat there must be some region   containing
                           ðx 0 ; y 0 Þ as an interior point for which @P=@y   @Q=@x > 0.  If   is the boundary of  ,then by Green’s
                           theorem
                                                                  @Q  @P
                                                  þ            ðð
                                                                         dx dy > 0
                                                    Pdx þ Qdy ¼
                                                                  @x  @y

                                                   þ
                           contradicting the hypothesis that Pdx þ Qdy ¼ 0for all closed curves in r. Thus @Q=@x   @P=@y cannot
                           be positive.
                              Similarly, we can show that @Q=@x   @P=@y cannot be negative, and it follows that it must be identically
                           zero, i.e., @P=@y ¼ @Q=@x identically in r.
                     10.12. Let P and Q be defined as in Problem 10.11.  Prove that a                  B
                                                           ð B                             D
                           necessary and sufficient condition that  Pdx þ Qdy be inde-
                                                                                       C 1
                                                            A
                           pendent of the path in r joining points A and B is that  A
                                                                                         C 2   E
                           @P=@y ¼ @Q=@x identically in r.
                                                                                        Fig. 10-12
                           Sufficiency.  If @P=@y ¼ @Q=@x,then byProblem 10.11,
                                              ð
                                                 Pdx þ Qdy ¼ 0
                                            ADBEA
                           (see Fig. 10-12).  From this, omitting for brevity the integrand Pdx þ Qdy,we have
                                           ð   ð         ð     ð    ð             ð   ð
                                                 ¼ 0;                    and so
                                             þ             ¼     ¼                  ¼
                                                                                  C 1  C 2
                                          ADB  BEA      ADB   BEA  AEB
                           i.e., the integral is independent of the path.
                           Necessity.
                              If the integral is independent of the path, then for all paths C 1 and C 2 in r we have
                                               ð    ð      ð    ð            ð
                                                      ;              and        ¼ 0
                                                  ¼          ¼
                                                C 1  C 2
                                                          ADB  AEB          ADBEA
                           From this it follows that the line integral around any closed path in r is zero, and hence by Problem 10.11
                           that @P=@y ¼ @Q=@x.
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