Page 354 - Schaum's Outline of Theory and Problems of Advanced Calculus
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CHAP. 13]                         FOURIER SERIES                                345


                           (a) Multiplying
                                                           X       n x      n x
                                                           1
                                                              a n cos  þ b n sin
                                                                    L        L
                                                   f ðxÞ¼ A þ                                         ð1Þ
                                                           n¼1
                                   m x
                              by cos   and integrating from  L to L,using Problem 13.3, we have
                                    L
                                  ð L      m x      ð  L  m x
                                     f ðxÞ cos  dx ¼ A  cos  dx
                                    L       L         L    L
                                                         ð                    ð
                                                    1     L                    L
                                                    X          m x   n x            m x   n x
                                                            cos   cos            cos   sin   dx
                                                       a n              dx þ b n
                                                  þ             L     L              L     L
                                                    n¼1    L                    L
                                                 ¼ a m L  if m 6¼ 0
                                                    1  ð  L   m x
                              Thus             a m ¼    f ðxÞ cos  dx  if m ¼ 1; 2; 3; .. .
                                                    L  L       L
                                               m x
                           (b) Multiplying (1)by sin  and integrating from  L to L,using Problem 13.3, we have
                                                L
                                  ð  L     m x      ð L   m x
                                     f ðxÞ sin  dx ¼ A  sin  dx
                                    L       L         L    L
                                                         ð  L                 ð L
                                                     1
                                                    X          m x   n x           m x    n x
                                                            sin   cos            sin   sin   dx
                                                       a n              dx þ b n
                                                  þ             L     L             L      L
                                                    n¼1    L                    L
                                                 ¼ b m L
                                                    1  ð  L   m x
                              Thus              b m ¼   f ðxÞ sin  dx  if m ¼ 1; 2; 3; .. .
                                                    L  L       L
                           (c)  Integrating of (1) from  L to L,using Problem 13.2, gives
                                                 L                       1  L
                                                ð                          ð
                                                   f ðxÞ dx ¼ 2AL  or  A ¼    f ðxÞ dx
                                                 L                      2L  L
                                                                        1  ð  L           a 0
                                                                                           .
                                  Putting m ¼ 0inthe result of part (a), we find a 0 ¼  f ðxÞ dx and so A ¼
                                                                       L  L               2
                                  The above results also hold when the integration limits  L; L are replaced by c; c þ 2L:
                                  Note that in all parts above, interchange of summation and integration is valid because the series is
                              assumed to converge uniformly to f ðxÞ in ð L; LÞ. Even when this assumption is not warranted, the
                              coefficients a m and b m as obtained above are called Fourier coefficients corresponding to f ðxÞ, and the
                              corresponding series with these values of a m and b m is called the Fourier series corresponding to f ðxÞ.
                              An important problem in this case is to investigate conditions under which this series actually converges
                              to f ðxÞ. Sufficient conditions for this convergence are the Dirichlet conditions established in Problems
                              13.18 through 13.23.


                     13.5. (a) Find the Fourier coefficients corresponding to the function

                                                        0   5 < x < 0
                                                        3   0 < x < 5
                                                 f ðxÞ¼                 Period ¼ 10
                           (b) Write the corresponding Fourier series.
                           (c) How should f ðxÞ be defined at x ¼ 5; x ¼ 0; and x ¼ 5in order that the Fourier series will
                              converge to f ðxÞ for  5 @ x @ 5?
                              The graph of f ðxÞ is shown in Fig. 13-6.
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