Page 124 - Schaum's Outline of Theory and Problems of Electric Circuits
P. 124

WAVEFORMS AND SIGNALS
               CHAP. 6]
















                                                        Fig. 6-12                                    113
                   2
               0.368 ¼ 0:135, respectively, also belong to the curve.  Using the preceding indicators, the curve may be drawn with
               a rather good approximation (see Fig. 6-12).

                                                                                                st
               EXAMPLE 6.21 (a) Show that the rate of change with respect to time of an exponential function v ¼ Ae is at any
               moment proportional to the value of the function at that moment.  (b) Show that any linear combination of an
               exponential function and its n derivatives is proportional to the function itself.  Find the coefficient of proportion-
               ality.
               (a) The rate of change of a function is equal to the derivative of the function, which, for the given exponential
                   function, is
                                                      dv     st
                                                        ¼ sAe ¼ sv
                                                      dt
               (b) Using the result of (a) we get
                                                       n
                                                      d v   n  st  n
                                                          ¼ s Ae ¼ s v
                                                       dt n
                                                         n
                                              dv        d v                  n
                                       a 0 v þ a 1  þ     þ a n  n  ¼ða 0 þ a 1 s þ     þ a n s Þv ¼ Hv  ð35Þ
                                              dt         dt
                   where                            H ¼ a 0 þ a 1 s þ     þ a n s n                  (36)
               Specifying and Plotting f ðtÞ¼ Ae  at  þ B
               We often encounter the function
                                                              at
                                                     f ðtÞ¼ Ae  þ B                                 ð37Þ
               This function is completely specified by the three numbers A, B,and a defined as

                    A ¼ initial value   final value  B ¼ final value   a ¼ inverse of the time constant
               or, in another form,
                        Initial value f ð0Þ¼ A þ B  Final value f ð1Þ ¼ B    Time constant ¼ 1=a



               EXAMPLE 6.22 Find a function vðtÞ which decays exponentially from 5 V at t ¼ 0to 1 Vat t ¼1 with a time
               constant of 3 s.  Plot vðtÞ using the technique of Example 6.20.
                                           t=
                   From (37) we have vðtÞ¼ Ae  þ B.  Now vð0Þ¼ A þ B ¼ 5, vð1Þ ¼ B ¼ 1, A ¼ 4, and   ¼ 3.  Thus
                                                             t=3
                                                     vðtÞ¼ 4e  þ 1
                   The preceding result can be generalized in the following form:
                                       vðtÞ¼ðinitial value   final valueÞe  t=   þðfinal valueÞ
                   The plot is shown in Fig. 6-13.
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