Page 53 - Schaum's Outline of Theory and Problems of Electric Circuits
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                               Fig. 4-6          ANALYSIS METHODS                               [CHAP. 4
                                                                            Fig. 4-7

               The ´ venin too).  The output resistance is found by dividing the open-circuited voltage to the short-
               circuited current at the desired node.  The short-circuited current is found in Section 4.6.



               4.6  TRANSFER RESISTANCE
                   A driving voltage in one part of a network results in currents in all the network branches.  For
               example, a voltage source applied to a passive network results in an output current in that part of the
               network where a load resistance has been connected.  In such a case the network has an overall transfer
               resistance.  Consider the passive network suggested in Fig. 4-7, where the voltage source has been
               designated as V r and the output current as I s . The mesh current equation for I s contains only one
               term, the one resulting from V r in the numerator determinant:

                                                  1s                rs
                                        I s ¼ð0Þ     þ     þ 0 þ V r   þ 0 þ
                                                  R                 R
               The network transfer resistance is the ratio of V r to I s :
                                                                 R
                                                     R transfer;rs ¼
                                                                 rs
               Because the resistance matrix is symmetric,   ¼   , and so
                                                       rs
                                                            sr
                                                  R transfer;rs ¼ R transfer;sr
               This expresses an important property of linear networks: If a certain voltage in mesh r gives rise to a
               certain current in mesh s, then the same voltage in mesh s produces the same current in mesh r.
                   Consider now the more general situation of an n-mesh network containing a number of voltage
               sources. The solution for the current in mesh k can be rewritten in terms of input and transfer
               resistances [refer to (7), (8), and (9) of Example 4.4]:

                                 V 1             V k 1      V k       V kþ1             V n
                          I k ¼        þ     þ           þ       þ            þ     þ
                              R transfer;1k  R transfer;ðk 1Þk  R input;k  R transfer;ðkþ1Þk  R transfer;nk
               There is nothing new here mathematically, but in this form the current equation does illustrate the
               superposition principle very clearly, showing how the resistances control the effects which the voltage
               sources have on a particular mesh current.  A source far removed from mesh k will have a high transfer
               resistance into that mesh and will therefore contribute very little to I k .  Source V k , and others in meshes
               adjacent to mesh k, will provide the greater part of I k .



               4.7  NETWORK REDUCTION

                   The mesh current and node voltage methods are the principal techniques of circuit analysis.  How-
               ever, the equivalent resistance of series and parallel branches (Sections 3.4 and 3.5), combined with the
               voltage and current division rules, provide another method of analyzing a network.  This method is
               tedious and usually requires the drawing of several additional circuits.  Even so, the process of reducing
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