Page 309 - Semiconductor For Micro- and Nanotechnology An Introduction For Engineers
P. 309

Interacting Subsystems
                Abrupt
                Junction     We  expect the junction as a whole also to be charge neutral. From
                             Figure 7.17 we see that the space charge is negative on the P side and
                Space Charge
                             positive on the N side. For an abrupt profile model, the space charge has a
                Layer Width
                             constant negative value over the entire P depletion region and a constant
                             positive value over the entire N depletion region, so that for overall
                             charge neutrality we require that
                                                     -      +
                                                 x N =  x N                      (7.160)
                                                  P  a   N  d
                             that is, the density of negative space charge on the left of the junction in
                             the P region times the left width equals the density of positive space
                             charge to the right of the junction in the N region times the right width. In
                             general, the depletion width is

                                                 W =  x +  x                     (7.161)
                                                       N   P
                             Hence both widths are to be determined, which means that we need an
                             additional equation.  This is provided by the Poisson equation (7.154)
                             applied to the depletion region only. We already know the voltage drop
                             over the depletion region, the built-in voltage  V  . Therefore, it is pru-
                                                                    bi
                             dent to integrate the 1D Poisson equation over the depletion region, to
                             obtain the voltage drop

                                            x  x          x  x
                                                2
                                               ∂ ψ            
                                    Vx() =    ∫ ∫  --------- xd  xd =   ∫ ∫  ρ x xd =  V bi  (7.162)
                                                               d
                                               ∂x 2           
                                            0  0          0  0
                             Due to the simple form of the SCL, we then obtain, after integration, that
                                            -           -
                                         qN a  2   – qN a  2  ( V )
                                                    ------------- x +
                                         ---------- x =
                                          2ε   P    2ε   N  bi Abrupt        (7.163)
                             Using (7.160) to eliminate one of the variables from (7.163), solving the
                             resultant quadratic equation and then back substituting this value into
                             (7.160) for the other variable, we obtain that





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