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α HK−ref  and α LK−ref . Thus use Case C (discussed later) for sandwich components. The method of Shiras et
                    al. (1950) can be used to check for distribution of NKs.

                    Case B. Assume that the distributions of NKs determined from the Fenske equation at total reflux are also
                    valid at minimum reflux. In this case the Dx     NK,dist  values are obtained from the Fenske equation as

                    described earlier. Again solve Eq. (7-33) for the φ value between the relative volatilities of the two keys.
                    This φ, the Fenske values of Dx     NK,dist,  and the Dx LK,dist  and Dx HK,dist  values obtained from Eqs. (7-36) and
                    (7-37) are used in Eq. (7-29) to find V . Then Eqs. (7-38) and (7-35) are used to calculate D and L .
                                                                                                                                      min
                                                                min
                    This procedure is illustrated in Example 7-2.
                    Case C. Exact solution without further assumptions. Equation (7-33) is a polynomial with C roots. Solve
                    this equation for all values of φ lying between the relative volatilities of all components,

                                      α LNK,1−ref  < φ  < α LNK,2−ref  < φ  < α LK−ref  < φ  < α HK−ref  < φ  < α HNK,1−ref
                                                                         2
                                                      1
                                                                                                           4
                                                                                          3
                    This gives C-1 valid roots. Now write Eq. (7-29) C-1 times; once for each value of φ. We now have C-1
                    equations and C-1 unknowns (V  and Dx           i,dist  for all LNK and HNK). Solve these simultaneous equations
                                                        min
                    and then obtain D from Eq. (7-38) and L  from Eq. (7-35). A sandwich component problem that must
                                                                  min
                    use this approach is given in Problem 7.D15.
                    In general, Eq. (7-33) will be of order C in φ where C is the number of components. Saturated liquid and
                    saturated vapor feeds are special cases and, after simplification, are of order C-1. If the resulting
                    equation is quadratic, the quadratic formula can be used to find the roots. Otherwise, a root-finding
                    method should be employed. If only one root, α       LK−ref  > φ > α HK−ref , is desired, a good first guess is to

                    assume φ = (α   LK−ref  + α HK−ref )/2.

                    The results of the Underwood equations will only be accurate if the basic assumption of constant relative
                    volatility and CMO are valid. For small variations in α a geometric average calculated as




                                                                                                                                (7-39)

                    can be used as an approximation. Application of the Underwood equations to systems with multiple feeds
                    was studied by Barnes et al. (1972).


                      Example 7-2. Underwood equations

                      For the distillation problem given in Example 7-1 find the minimum reflux ratio. Use a basis of 100
                      kmol/h of feed.

                      Solution

                      A. Define. The problem was sketched in Example 7-1. We now wish to find (L/D)                 min .

                      B. Explore. Since the relative volatilities are approximately constant, the Underwood equations can
                         easily be used to estimate the minimum reflux ratio.

                      C. Plan. This problem fits into Case A or Case B. We can calculate Dx            i,dist  values as described in
                         Cases A or B, Eqs. (7-36) and (7-37), and solve Eq. (7-33) for φ where φ lies between the
                         relative volatilities of the two keys 0.21 < φ < 1.00. Then V  can be found from Eq. (7-29), D
                                                                                             min
                         from Eq. (7-38) and L  from Eq. (7-35).
                                                  min
                      D. Do It. Follow Case B analysis. Since the feed is a saturated vapor, q = 0 and ΔV            feed  = F (1 − q) =
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