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                 102   Mechanical Engineering Design
                                              The last assumption depends upon the axisymmetry of the member, so it does not
                                          hold true for noncircular cross sections. Consequently, Eqs. (3–35) through (3–37)
                                          apply only to circular sections. For a solid round section,
                                                                             πd 4
                                                                         J =                               (3–38)
                                                                              32
                                          where d is the diameter of the bar. For a hollow round section,

                                                                          π    4  4
                                                                      J =    d − d i                       (3–39)
                                                                              o
                                                                          32
                                          where the subscripts o and i refer to the outside and inside diameters, respectively.
                                              There are some applications in machinery for noncircular cross section members
                                          and shafts where a regular polygonal cross section is useful in transmitting torque to a
                                          gear or pulley that can have an axial change in position. Because no key or keyway is
                                          needed, the possibility of a lost key is avoided. The development of equations for stress
                                          and deflection for torsional loading of noncircular cross sections can be obtained from
                                          the mathematical theory of elasticity. In general, the shear stress does not vary linearly
                                          with the distance from the axis, and depends on the specific cross section. In fact, for a
                                          rectangular section bar the shear stress is zero at the corners where the distance from
                                          the axis is the largest. The maximum shearing stress in a rectangular b × c section bar
                                          occurs in the middle of the longest side b and is of the magnitude
                                                                       T   .  T      1.8
                                                               τ max =    =      3 +                       (3–40)
                                                                      αbc 2  bc 2    b/c
                                          where b is the width (longer side) and c is the thickness (shorter side). They can not be
                                          interchanged. The parameter α is a factor that is a function of the ratio b/c as shown in
                                                          5
                                          the following table. The angle of twist is given by
                                                                             Tl
                                                                        θ =                                (3–41)
                                                                               3
                                                                            βbc G
                                          where β is a function of b/c, as shown in the table.
                  b/c    1.00    1.50     1.75    2.00    2.50    3.00    4.00    6.00    8.00     10      ∞

                   α     0.208   0.231   0.239   0.246   0.258   0.267   0.282    0.299   0.307   0.313   0.333
                   β     0.141   0.196   0.214   0.228   0.249   0.263   0.281    0.299   0.307   0.313   0.333

                                          Equation (3–40) is also approximately valid for equal-sided angles; these can be con-
                                          sidered as two rectangles, each of which is capable of carrying half the torque. 6
                                              It is often necessary to obtain the torque T from a consideration of the power and
                                          speed of a rotating shaft. For convenience when U. S. Customary units are used, three
                                          forms of this relation are
                                                                   FV       2πTn        Tn
                                                             H =        =           =                      (3–42)
                                                                  33 000  33 000(12)  63 025


                                          5 S. Timoshenko, Strength of Materials, Part I, 3rd ed., D. Van Nostrand Company, NewYork, 1955, p. 290.
                                          6 For other sections see W. C. Young and R. G. Budynas, Roark’s Formulas for Stress and Strain, 7th ed.,
                                          McGraw-Hill, New York, 2002.
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