Page 125 - Shigley's Mechanical Engineering Design
P. 125

bud29281_ch03_071-146.qxd  11/24/09  3:01PM  Page 100 ntt 203:MHDQ196:bud29281:0073529281:bud29281_pagefiles:







                 100   Mechanical Engineering Design
                                              The magnitude of the idealized transverse shear stress profile through the beam
                                          depth will be as shown in Fig. 3–20d.
                                              (b) The bending stresses at each point of interest are


                                Answer         σ a =  My a  =  (1098)(0)  = 0 psi
                                                     I       2.50

                                                          My b    (1098)(1.24)
                                               σ b = σ c =−   =−             =−545 psi
                                                           I         2.50
                                                     My d     (1098)(1.50)
                                               σ d =−     =−             =−659 psi
                                                       I         2.50
                                              (c) Now at each point of interest, consider a stress element that includes the bend-
                                          ing stress and the transverse shear stress. The maximum shear stress for each stress
                                          element can be determined by Mohr’s circle, or analytically by Eq. (3–14) with
                                          σ y = 0,

                                                                             σ
                                                                                2
                                                                    τ max =      + τ  2
                                                                              2
                                          Thus, at each point

                                                                             2
                                                            τ max,a =  0 + (828) = 828 psi

                                                                            2
                                                                      −545

                                                                                    2
                                                            τ max,b =         + (715) = 765 psi
                                                                        2

                                                                            2
                                                                      −545

                                                                                     2
                                                            τ max,c =         + (52.2) = 277 psi
                                                                        2

                                                                            2
                                                                      −659

                                                            τ max,d =         + 0 = 330 psi
                                                                        2
                                Answer    Interestingly, the critical location is at point a where the maximum shear stress is the
                                          largest, even though the bending stress is zero. The next critical location is at point b in
                                          the web, where the thin web thickness dramatically increases the transverse shear stress
                                          compared to points c or d. These results are counterintuitive, since both points a and b
                                          turn out to be more critical than point d, even though the bending stress is maximum at
                                          point d. The thin web and wide flange increase the impact of the transverse shear stress.
                                          If the beam length to height ratio were increased, the critical point would move from
                                          point a to point b, since the transverse shear stress at point a would remain constant,
                                          but the bending stress at point b would increase. The designer should be particularly
                                          alert to the possibility of the critical stress element not being on the outer surface with
                                          cross sections that get wider farther from the neutral axis, particularly in cases with
                                          thin web sections and wide flanges. For rectangular and circular cross sections, how-
                                          ever, the maximum bending stresses at the outer surfaces will dominate, as was shown
                                          in Fig. 3–19.
   120   121   122   123   124   125   126   127   128   129   130