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                 308   Mechanical Engineering Design
                  Table 6–8                Intersecting Equations      Intersection Coordinates

                  Amplitude and Steady           2       2                         2 2 2
                                                                                 r S S

                  Coordinates of Strength    S a  +  S m  = 1              S a =     e y
                                                                                  2
                                                                                      2 2
                                             S e     S y                         S + r S y
                                                                                  e
                  and Important
                  Intersections in First                                        S a
                                           Load line r = S a /S m          S m =
                  Quadrant for ASME-                                            r
                  Elliptic and Langer       S a  S m                            rS y
                                              +    = 1                     S a =
                  Failure Criteria          S y  S y                            1 + r
                                                                                 S y
                                           Load line r = S a /S m          S m =
                                                                                1 + r
                                                2       2
                                                                                      2
                                             S a     S m                          2S y S e
                                                 +       = 1               S a = 0,  2  2
                                             S e     S y                          S + S
                                                                                   e   y
                                            S a  S m
                                              +    = 1                     S m = S y − S a ,r crit = S a /S m
                                            S y  S y
                                           Fatigue factor of safety

                                                                        1
                                                           n f =
                                                                      2        	 2
                                                                 (σ a /S e ) + σ m /S y

                                          criteria. The first column gives the intersecting equations and the second column the
                                          intersection coordinates.
                                              There are two ways to proceed with a typical analysis. One method is to assume
                                          that fatigue occurs first and use one of Eqs. (6–45) to (6–48) to determine n or size,
                                          depending on the task. Most often fatigue is the governing failure mode.  Then
                                          follow with a static check. If static failure governs then the analysis is repeated using
                                          Eq. (6–49).
                                              Alternatively, one could use the tables. Determine the load line and establish which
                                          criterion the load line intersects first and use the corresponding equations in the tables.
                                              Some examples will help solidify the ideas just discussed.





                       EXAMPLE 6–10       A 1.5-in-diameter bar has been machined from an AISI 1050 cold-drawn bar. This part
                                          is to withstand a fluctuating tensile load varying from 0 to 16 kip. Because of the ends,
                                                                                                       6
                                          and the fillet radius, a fatigue stress-concentration factor K f is 1.85 for 10 or larger
                                          life. Find  S a and  S m and the factor of safety guarding against fatigue and first-cycle
                                          yielding, using (a) the Gerber fatigue line and (b) the ASME-elliptic fatigue line.

                                Solution  We begin with some preliminaries. From Table A–20, S ut = 100 kpsi and S y = 84 kpsi.
                                          Note that F a = F m = 8 kip. The Marin factors are, deterministically,
                                          k a = 2.70(100) −0.265  = 0.797: Eq. (6–19), Table 6–2, p. 288
                                          k b = 1 (axial loading, see k c )
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