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                 488   Mechanical Engineering Design
                  Table 9–2

                  Bending Properties of Fillet Welds*

                  Weld                    Throat Area          Location of G       Unit Second Moment of Area
                  1.                                                                    d 3
                                        A = 0.707hd              x ¯ = 0            I u =
                         G                                                               12
                           d                                     y ¯ = d/2
                     y

                  2.     b                                                              d 3
                                        A = 1.414hd              x ¯ = b/2          I u =  6
                                                                 y ¯ = d/2
                          G   d
                     y
                        x
                  3.      b                                                             bd  2
                                        A = 1.414hb              x ¯ = b/2          I u =  2
                                                                 y ¯ = d/2
                           G  d
                     y
                        x
                  4.      b                                           b 2               d 2
                                        A = 0.707h(2b   d)       ¯ x =              I u =  (6b + d )
                                                                    2b + d               12
                         G    d                                  y ¯   d/2
                     y
                        x

                  5.      b                                                             2d  3
                                                                                                2
                                        A = 0.707h(b   2d)       x ¯ = b/2          I u =   − 2d ¯y + (b + 2d ) ¯y 2
                     y                                                                    3
                           G                                          d 2
                               d                                 ¯ y =
                                                                    b + 2d
                         x
                  6.      b                                                             d 2
                                        A = 1.414h(b   d)        x ¯ = b/2          I u =  (3b + d )
                                                                                         6
                                                                 y ¯ = d/2
                           G   d
                     y
                         x
                  7.   b                                                                2d  3
                                                                                                2
                                        A = 0.707h(b   2d)       x ¯ = b/2          I u =   − 2d ¯y + (b + 2d ) ¯y 2
                          y                                                               3
                                                                      d 2
                        G    d                                   ¯ y =
                                                                    b + 2d
                      x
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