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The Elements of Six Sigma and Their Determination




                               Figure 2.12 Quick visual check for normality in Example 2.4.1.  61


                        ber expected in the distribution being tested, in this case the normal
                        distribution. Sometimes this test is called “the goodness of fit test.”
                         The boundaries are chosen for convenience, with five being a com-
                        monly used number. The boundary limits are used to generate a prob-
                        ability for the expected frequency. This is done in the case of the nor-
                        mal  distribution  by  calculating  the  z value  based  on  the  boundary
                        limit and the average and standard distribution of the data set, in the
                        following manner:

                        1. List the data set in ascending order.
                        2. Determine the number of boundaries (variable k) to be used in this
                          test.
                        3. Let m i be the number of sample values observed in each boundary
                        4. Calculate  a  z value  for  each  boundary.  For  the  two  outermost
                          boundaries,  there  is  one  single  z value.  For  inside  boundaries,
                          there are two z values.
                        5. Calculate the expected frequency for each boundary by determin-
                          ing the P i = f(z) and multiplying that number by the total number
                          in the data set.
                        6. Determine  the  contribution  of  each  boundary  to  total  chi-square
                          value through the formula
                                         (m i – nP i ) 2
                                     2
                                      =           ;   with k – 1 DOF         (2.16)
                                           nP i
                         A hypothesis reject, which indicates that the distribution is not nor-
                        mal is when        , which obtained from a   table for   = 1 – confi-
                                                              2
                                        2
                                   2
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