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0066_frame_C27  Page 15  Wednesday, January 9, 2002  7:10 PM



























                       FIGURE 27.17  Nyquist diagram.



















                       FIGURE 27.18  Nyquist diagram and root locus of Example 4.
                       The Nyquist stability criterion can now be stated as follows:

                         A necessary and sufficient condition for the closed-loop stability of a system defined by the loop
                         transfer function L(s) is that
                                                          Z =  N +  P                         (27.12)

                         be equal to zero, where N is the net number of encirclements of the −1 point in the L(s)-plane, and
                         P is the number of unstable poles of the loop transfer function L(s).

                       Example 4
                       Consider the system with the loop transfer function
                                                                      2  2s +
                                                                     s –
                                                                            2
                                              KL s() =  KG s()Hs() =  K----------------------------------  (27.13)
                                                                   ss + 1) s + 2)
                                                                    (
                                                                         (
                       Let us determine the range of the gain K such that the closed-loop system is stable. Since there is a
                       pole at s = 0, we need to modify the Nyquist path to detour around the origin. The contour is shown
                       in Fig. 27.18(a), where the detour is chosen to be a semicircle of radius approaching zero in the limit.
                       We use the following procedure to sketch the Nyquist plot in Fig. 27.18(b):
                                                 +
                         1. Determine L(jω) as ω → 0  : L(s) is of system type 1 and thus
                                                            1
                                                    Ljw) ≈  ----- =  ∞ – 90°
                                                      (
                                                                  ∠
                                                            jw
                            according to Table 27.2.

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