Page 481 - Bird R.B. Transport phenomena
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§15.4  The d-Forms of the Macroscopic Balances  461

                            in  which  у  = C /C , a  quantity  which  varies  from  about  1.1  to  1.667  for  gases.  Here  we
                                          p
                                             v
                             have used the fact that C /R  = y/(y  -  1) for  an ideal gas. When  Eq. 15.3-12 is solved  for v 2
                                                 p
                             we get


                             On  physical grounds, the radicand  cannot be negative. It can be shown  (see Problem  15B.4)
                             that, when the radicand  is zero, the velocity  of the final  stream is sonic. Therefore, in general
                             one  of the solutions for v 2  is supersonic and one is subsonic. Only the lower  (subsonic) solu-
                             tion  can be  obtained  in the turbulent  mixing process under  consideration, since supersonic
                             duct flow  is  unstable.  The transition  from  supersonic to subsonic duct flow  is  illustrated in
                             Example 11.4-7.
                                Once the velocity v  is known, the pressure and temperature may be calculated  from Eqs.
                                               2
                             15.3-7 and 11. The mechanical energy balance can be used to get (E  + £ t,).
                                                                                  c


       §15.4  THE d-FORMS OF THE MACROSCOPIC BALANCES
                             The estimation  of  E v in the mechanical energy balance and  Q in the total energy  balance
                             often  presents some difficulties  in nonisothermal systems.
                                For example, for E v, consider the following  two nonisothermal  situations:

                                 a.  For liquids, the average flow velocity in a tube  of constant  cross section is nearly
                                   constant.  However,  the  viscosity  may  change  markedly  in  the  direction  of  the
                                   flow because  of the temperature  changes, so that /  in  Eq.  7.5-9 changes with  dis-
                                   tance. Hence Eq. 7.5-9 cannot be applied  to the entire pipe.
                                b.  For  gases,  the  viscosity  does  not  change  much  with  pressure,  so  that  the  local
                                   Reynolds  number  and  local  friction  factor  are  nearly  constant  for  ducts  of  con-
                                   stant  cross  section.  However,  the  average  velocity  may  change  considerably
                                   along  the duct  as  a result  of  the change  in density  with  temperature.  Hence  Eq.
                                   7.5-9 cannot be applied  to the entire duct.
                                 Similarly for pipe flow with the wall temperature changing with distance, it may be
                             necessary  to use  local heat  transfer  coefficients.  For  such  a  situation,  we  can  write  Eq.
                             15.1-3 on an incremental basis and generate a differential  equation. Or the cross sectional
                             area  of the conduit  may be changing  with  downstream  distance, and  this situation  also
                             results in a need  for handling the problem on an incremental basis.
                                 It is therefore  useful  to rewrite the steady-state macroscopic mechanical energy bal-
                             ance and the total energy balance by taking planes 1 and  2 to be a differential  distance dl
                             apart. We then obtain what we call the "d-forms"  of the balances:


        The rf°Form of the Mechanical Energy Balance
                             If we take planes 1 and 2 to be a differential  distance apart, then we may write  Eq. 15.2-2
                             in the following  differential  form  (assuming flat velocity  profiles):

                                                                 ^         -  dE v               (15.4-1)

                             Then using Eq. 7.5-9 for a differential  length dl, we write
                                                                           2
                                                    vdv  + gdh + ldp  = dW-  \v •£-dl            (15.4-2)
                                                               t 3           K h
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