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56
                                                  Water Sources: Groundwater
                                         Chapter 3
                                      Solution 2 (SI Units):
                                                               From Eq. (3.12): s = [Q∕(4  T)][W(u)]
                                                                             = [3,815∕(4 × 3.14 × 398.72)][W(u)]
                                                                             = 0.72 m[W(u)].
                                                                                2
                                                               From Eq. (3.13): u = r S∕(4Tt)
                                                                                     2
                                                                             = (0.3048) × 3.43 × 10 ∕(4 × 398.72t)
                                                                                      −9
                                                                             = (2.0 × 10 )∕t.
                                          For various values of t, compute u, then from Table 3.2 obtain the well function, W(u), for the calculation of drawdown. The
                                      values of drawdown for various values of time are given in Table 3.3.  −5
                                    3.10.2 Semilogarithmic Approximation               usually chosen one log cycle apart. Equation (3.20) then
                                                                                       reduces to
                                    It was recognized that when u is small, the sum of the terms
                                    beyond ln u in the series expansion of W(u) (Eq. 3.14) is  T = 264 Q∕Δs  (US customary units)  (3.21a)
                                    relatively insignificant. The Theis equation (Eq. 3.12) then
                                    reduces to                                         where T is the transmissivity, in gpd/ft; Q is the well flow, in
                                                                                       gpm; and Δs is the change in drawdown, in ft, over one log
                                                                2
                                           s = [Q∕(4  T)]{ln[(4Tt)∕(r S)] − 0.5772}
                                                                                       cycle of time.
                                                                 2
                                           s = Q∕(4  T) ln[(2.25Tt)∕(r S)]  (SI units) (3.17)  An equivalent equation using the SI units is
                                                          3
                                                 3
                                    where Q is in m /d, T in m /d/m, t in days, and r in m.        T = 0.1833Q∕Δs  (SI units)   (3.21b)
                                        When Q is in gpm, T in gpd/ft, t in days, and r in ft, the
                                                                                                                  3
                                    equation becomes                                   where T is the transmissivity, in m /d/m; Q is the well flow,
                                                                                          3
                                                                                       in m /d; and Δs is the change in drawdown, in m, over one
                                                            2
                                     s = 264(Q∕T) log[(0.3Tt)∕(r S)] (US customary units)
                                                                                       log cycle of time.
                                                                               (3.18)     The coefficient of storage of the aquifer can be calculated
                                                                                       from the intercept of the straight line on the time axis at zero
                                        A graphical solution was proposed for this equation. If  drawdown, provided that time is converted to days. For zero
                                    the drawdown is measured in a particular observation well  drawdown, Eq. (3.18) gives
                                    (fixed r) at several values of t, the equation becomes
                                                                                                                        2
                                                                                                  0 = 264(Q∕T) log[0.3Tt ∕(r S)]
                                                                                                                     0
                                                    s = 264(Q∕T) log(Ct)
                                                                                       that is,
                                    where
                                                                                                               2
                                                                2
                                                      C = 0.3 T∕(r S)                                   0.3Tt ∕(r S) = 1
                                                                                                            0
                                        If, on semilogarithmic paper, the values of drawdown are  which gives
                                    plotted on the arithmetic scale and time on the logarithmic
                                                                                                          2
                                    scale, the resulting graph should be a straight line for higher  S = 0.3Tt ∕r  (US customary units)  (3.22a)
                                                                                                       0
                                    values of t where the approximation is valid. The graph is
                                    referred to as the time–drawdown curve. On this straight line  where S is the coefficient of storage of an aquifier, dimen-
                                    an arbitrary choice of times t and t can be made and the  sionless; T is the transmissivity, gpd/ft; t is the time at zero
                                                                                                                       0
                                                                  2
                                                            1
                                    corresponding values of s and s recorded. Inserting these  drawdown, d; and r is the distance between an observation
                                                               2
                                                         1
                                    values in Eq. (3.18), we obtain                    well and a pumping well, ft.
                                                                                          An equivalent equation using the SI units is
                                                s − s = 264(Q∕T) log(t ∕t )    (3.19)
                                                 2   1              2  1
                                                                                                    S = 2.24Tt ∕r 2  (SI units)  (3.22b)
                                                                                                            0
                                    Solving for T,
                                                                                       where S is the coefficient of storage of an aquifier, dimen-
                                                T = 264 Q log(t ∕t )∕(s − s )  (3.20)                            3
                                                                   2
                                                               1
                                                             2
                                                                       1
                                                                                       sionless; T is the transmissivity, m /d/m; t is the time at zero
                                                                                                                       0
                                        Thus transmissivity is inversely proportional to the slope  drawdown, d; and r is the distance between an observation
                                    of the time–drawdown curve. For convenience, t and t are  well and a pumping well, m.
                                                                                2
                                                                           1
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