Page 114 - Wind Energy Handbook
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88                         AERODYNAMICS OF HORIZONTAL-AXIS WIND TURBINES


          angular momentum to the non-dimensional rate of change of axial momentum, is
          not changed because it deals with the whole flow through the disc and so uses
          average values. If drag is ignored for the present, Equation (3.59) becomes
                                              ºìa9(1   a)
                                    tan ö ¼                                    (3:81)
                                           a(1   a) þ (a9ºì) 2

          Hence
                                                         a
                                                      1
                                   (1   a)ºìa9  ¼         f
                                a(1   a) þ (ºìa9) 2       a9
                                                   ºì 1 þ
                                                           f
          which becomes

                            ( f   1)                            a9
                                        2 2
                                    2
                         2 2
                        º ì       a9   º ì (1   a)a9 þ a(1   a)1    ¼ 0        (3:82)
                               f                                 f
          A great simplification can be made to Equation (3.82) by ignoring the first term
          because, clearly, it disappears for much of the blade, where f ¼ 1, and for the tip
                              2
          region the value of a9 is very small. For tip speed ratios greater than 3 neglecting
          the first term makes negligible difference to the result.
                                                     a
                                        2 2
                                       º ì a9 ¼ a 1                            (3:83)
                                                     f

          As before, Equation (3.57) still applies
                                          d     1   a
                                             a ¼
                                          da9     a9

          From Equation (3.83)

                                      d       1        a
                                        a9 ¼      1   2
                                             2 2
                                     da     º ì        f
          Consequently
                                                a
                                                      2 2
                                    (1   a)1   2   ¼ º ì a9
                                                f
          which combined with Equation (3.83) gives

                                         2          1
                                      2
                                     a   (f þ 1)a þ  f ¼ 0
                                         3          3
          so
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