Page 345 - Characterization and Properties of Petroleum Fractions - M.R. Riazi
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            AT029-Manual
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                                           7. APPLICATIONS: ESTIMATION OF THERMOPHYSICAL PROPERTIES 325
            one compound (i.e., H 2 OorCO 2 ). However, when a hydro-
                                                                  heating values of other fuels are calculated as follows:
            carbon (C x H y ) is burned the only products are H 2 O and CO 2 .  HHV = 121 + 0.22 × 100 = 143 kJ/g or 61000 Btu/lb. The --`,```,`,``````,`,````,```,,-`-`,,`,,`,`,,`---
            Combustion is a reaction in which the enthalpy of products is
            less than enthalpy of reactants and as a result the heat of reac-  Hydrogen,  Methane,  Propane,  Carbon,  Sulfur,
            tion (enthalpy of products − enthalpy of reactants) is always  Fuel  H 2   CH 4     C 3 H 8   C      S
            negative. This heat of reaction is called heat of combustion  LHV, kJ/g  121  50    46.4    32.8     9.3
                             C
            and is shown by  H . Heat of combustion depends on the  HHV, kJ/g  143     55.5     50.4    32.8     9.3
            temperature at which the combustion takes place. The stan-
                                                   C
            dard temperature at which usually values of  H are reported  As it can be seen from these calculations, hydrogen has the
            is 25 C (298 K).                                      highest heating value and carbon has the lowest heating value.
                ◦
              Amount of heat released by burning one unit mass (i.e., kg,  Thus hydrogen is the best, while carbon is considered as the
            g, or lb) of a fuel is called heating value or calorific value and  worst fuel. Sulfur heating value is even less than carbon but
            has the unit of kJ/kg or Btu/lb (1 kJ/kg = 0.42993 Btu/lb). In  sulfur is not really considered as a fuel. Some values of HHV
            some cases for liquid fuels the heating values are given per  for several other fuels as reported by Felder and Rousseau
            unit volume (i.e., kJ/L of fuel), which differs from specific  [32] are given in Table 7.13. The calculated value of HHV of
            (mass unit) heating values by liquid density. If in the combus-  C is near the HHV of hard coal (i.e., solid form) as given in
            tion process produced H 2 O is considered as liquid, then the  Table 7.13. In natural gases since there are some hydrocar-
            heat produced is called gross heat of combustion or higher  bons heavier than methane, its heating value is somewhat
            heating value (HHV). When produced H 2 O is considered as  lower than that of pure methane.
            vapor (as in the actual cases), then the heat produced is called
            lower heating value (LHV). The LHV is also known as the net  Example 7.8 shows that the heating value generally in-
            heating value (NHV). The difference between HHV and LHV is  creases as the hydrogen content of fuel increases and car-
            due to the heat required to vaporize produced water from liq-  bon content decreases. In other words, as CH weight ratio
            uid to vapor form at the standard temperature (43.97 kJ/mol  increases the heating value decreases. Furthermore, presence
            or 2.443 kJ/g of H 2 O). The amount of H 2 O formed depends on  of sulfur further reduces the heating value. For this reason,
            the hydrogen content of fuel. If the hydrogen wt% of fuel is  some researchers have correlated HHV to wt% of C, H, S, N,
            H% then the relation between HHV and LHV is given as [30]:  and O content of fuel. For example, Tsonopoulos et al. [18]
                                                                  proposed the following relation for estimation of HHV of coal
                                                                  liquids:
            (7.61)         LHV = HHV − 0.22H%
                                                                   HHV [kJ/g] = 0.3506 (C%) + 1.1453 (H%) + 0.2054 (S%)
            where both LHV and HHV are in kJ/g. The heating values can  (7.62)  + 0.0617 (N%) − 0.0873 (O%)
                                                           f
            also be determined from standard heats of formation ( H 298 ).
                       f
            Values of  H 298  for any element (i.e., H 2 ,O 2 , C, S, etc.) is  S, N, and O are usually found in heavy fuels and aromatic rich
            zero and for formed molecules such as H 2 O are given in  fuels such as coal liquids. This equation predicts HHV of coal
            most thermodynamics references [12, 21, 31]. For example,  liquids with %AAD of 0.55 for some 130 fuels. This equation
            for H 2 O(g), CO 2 (g), CO(g), SO 2 ,CH 4 (g), C 2 H 6 (g), C 3 H 8 (g),  predicts HHV of pure C as 35 kJ/g. However, this equation is
            and n-C 10 H 22 the respective values of  H f  are −241.81,  not recommended for light fuels, petroleum fraction, or pure
                                                298
            −393.51, −110.53, −296.81, −74.52, −83.82, −104.68, and  compounds. There is a simpler relation for calculation of LHV
            −249.46 kJ/mol. The following example shows calculation of  of heavy fuels and petroleum fractions [30]:
            heating values from heats of formations.
                                                                 (7.63)   LHV [kJ/g] = 55.5 − 14.4 × SG − 0.32S%
                                                                  where S% is the sulfur wt% in the fuel. A very simple but
            Example 7.8—Calculate HHV and LHV of hydrogen, me-
            thane, propane, carbon, and sulfur from heats of formation.  approximate formula for calculation of HHV of crude oils is
                                                                  [26]:
                                                                 (7.64)          HHV = 51.9 − 8.8 × SG 2
            Solution—Here the calculation of heating value of CH 4
            is demonstrated and a similar approach can be used for  where HHV is in kJ/g (or MJ/kg) and SG is the specific gravity
            other fuels. The chemical reaction of combustion of CH 4 is  of crude and S% is the sulfur wt% of the crude. Accuracy of
                                                 C         C
            CH 4 (g) + 2O 2 (g) → 2H 2 O(g) + CO 2 (g) +  H , where  H =  these equations is usually about 1%. A typical crude oil has
                                                    f
            2 H 298 (H 2 O) +  H 298 (CO 2 ) −  H 298 (CH 4 ) −  H 298  (O 2 ) = 2×  heating value of about 10 500 cal/g (∼44 kJ/g). Increase in hy-
                                        f
                            f
                f
            (−241.835) + (−393.51) − (−74.8936) − (0) =−802.286 kJ/  drogen content of a fuel not only increases the heating value
            mol. Since the produced water is assumed to be in gas phase
            so the LHV is calculated as 802.286/16.04 = 50.01 kJ/g.
            This is equivalent to 11953 cal/g or 21500 Btu/lb. The         TABLE 7.13—Heating values of some fuels.
            HHV can be calculated by adding heat of vaporization of          Taken with permission from Ref. [32].
                                                                                             Higher heating value
            water (2 × 43.97 = 87.94 kJ/mol) to the molar LHV. HHV =     Fuel              kJ/g         Btu/lb
            802.286 + 87.94 = 890.2 kJ/mol or 55.5 kJ/g of CH 4 . Equa-
                                                                                                         7700
            tion (7.61) to convert LHV to HHV or vice versa using        Wood               18          15 000
                                                                         Hard coal
                                                                                            35
            H% of fuel may also be used. In this case, H% of CH 4 =      Crude oil          44          19 000
            (4/16) × 100 = 25 wt%. Thus HHV = 50 + 0.22 × 25 = 55.5      Natural gas        54          23 000
            kJ/g. Similarly for H 2 , LHV = 241.81/2.0 = 121 kJ/g. The   Hydrogen          143          61 000







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