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Guo, Boyun / Computer Assited Petroleum Production Engg 0750682701_chap06 Final Proof page 77 3.1.2007 8:40pm Compositor Name: SJoearun
WELL DELIVERABILITY 6/77
1,800
1,600 WPR
1,400 CPR
Wellhead Pressure (psia) 1,000
1,200
800
600
400
200
0
0 200 400 600 800 1,000 1,200 1,400 1,600 1,800 2,000
Gas Production Rate (Mscf/d)
Figure 6.3 Nodal analysis for Example Problem 6.5.
If the TPR is described by the Guo–Ghalambor model Example Problem 6.7 Use the following data to estimate
defined by Eq. (4.18), that is, the liquid production rate of an oil well:
1 2bM
144bp wf p hf þ Choke size: 64 1/64 in.
2
Reservoir pressure: 3,000 psia
b
144p wf þ M þN M þ N bM 2 Total measured depth: 7,000 ft
2
ln c p ffiffiffiffiffi Average inclination angle: 20 degrees
144p hf þ M þN N Tubing ID: 1.995 in.
2
Gas production rate: 1,000,000 scfd
144p wf þ M 144p hf þ M
tan 1 p ffiffiffiffiffi tan 1 p ffiffiffiffiffi Gas-specific gravity: 0.7 air ¼ 1
N N Oil-specific gravity: 0.85 H 2 O ¼ 1
Water cut: 30%
2
¼ a( cos u þ d e)L, (6:22) Water specific gravity: 1.05 H 2 O ¼ 1
3
and the CPR is given by Eq. (5.12), that is, Solid production rate: 1 ft =d
m
CR q Solid-specific gravity: 2.65 H 2 O ¼ 1
p hf ¼ , (6:23) Tubing head temperature: 100 8F
S n Bottom-hole temperature: 160 8F
solving Eqs. (6.21), (6.22), and (6.23) simultaneously will Absolute openflow (AOF): 2,000 bbl/d
give production rate q and wellhead pressure p hf : The Choke flow constant: 10
solution procedure has been coded in the spreadsheet pro- Choke GLR exponent: 0.546
gram WellheadNodalOil-GG.xls. Choke-size exponent: 1.89
2,500
WPR
CPR
2,000
Wellhead Pressure (psia) 1,500
1,000
500
0
0 1,000 2,000 3,000 4,000 5,000 6,000
Liquid Production Rate (bbl/d)
Figure 6.4 Nodal analysis for Example Problem 6.6.