Page 267 - Advanced Organic Chemistry Part A - Structure and Mechanisms, 5th ed (2007) - Carey _ Sundberg
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2.22. Figure 2.22Pa,b shows energy as a function of rotation for a series of 2-substituted  247
               acetaldehydes, with 
 = 0 in the syn conformation and 
 = 180 in the anti


                                                                                           PROBLEMS
               conformation. The calculations were done by the PM3 method. Figure 2.P22a
               represents the isolated molecule, while Figure 2.P22b represents an elliptical
               solvent cavity with a dielectric constant of 4.7, approximating CHCl . The
                                                                          3
               Table 2.22P gives the calculated rotational barriers. Discuss the following
               aspects of the data. (a) Rationalize the Br > Cl > F order of preference for
               anti conformation in the gas phase; (b) Why does the polar medium shift the
               equilibrium to favor more of the syn conformation?


                                    H          H    H         H
                                         O              H
                                  H       X  H       O  X      O
                                    H            X             H
                                    syn 0°      90°      anti 180°
































            Fig. 2.22P. (a) Rotational profile of the isolated molecules. (b) Rotational profile in solvent cavity
            with dielectric constant 4.7. Reproduced by permission of Elsevier.

          2.23. Provide a mechanistic explanation, including proposed transition structure(s), to
               account for the stereoselectivity observed in the following reactions:

                       a.
                                       1) 1.2 eq TiCl 4
                             O  OH       BH S(CH )      OH OH           OH OH
                                            .
                                                3 2
                                           3
                                                                    +  1      2
                          R 1     R 2  2) H+, H O     R 1  syn  R 2  R   anti  R
                                             2
                                       3) NaOH
                                                     The product has a high syn:anti ratio
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