Page 264 - Advanced Organic Chemistry Part A - Structure and Mechanisms, 5th ed (2007) - Carey _ Sundberg
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244                    c. The biosynthesis of valine by bacteria involves the following sequence:
                                                              O
     CHAPTER 2
                               (CH 3 ) 2 C  CHCO H                            (CH ) CHCHCO H
     Stereochemistry,                       2          (CH ) CHCCO H             3 2      2
                                                          3 2
                                                                  2
     Conformation,
     and Stereoselectivity         OH OH                                              NH 2
                              The stereochemistry of the reaction has been examined using the starting diol
                              in which each methyl group was separately replaced by CD . The diol-d of
                                                                               3
                                                                                         3
                              the 2R,3R configuration produces 2S,3S-valine-d , whereas the 2R,3S diol-d
                                                                      3                     3
                              produces 2S,3R-valine-d . From this information deduce whether the C(2)
                                                   3
                              and C(3) hydroxy are replaced with inversion or retention of configuration.
                              Show the basis for your conclusion.
                            d. A synthesis of the important biosynthetic intermediate mevalonic acid starts
                              with the enzymatic hydrolysis of the diester 14-C by pig liver esterase.
                              The pro-R ester group is selectively hydrolyzed. Draw a three-dimensional
                              structure of the product.
                                                                 CH 3
                                                        H CO CCH CCH CO CH 3
                                                                2
                                                         3
                                                                    2
                                                                       2
                                                            2
                                                                 OH
                                                                14-C
                       2.15. The structure of nonactin is shown below without any specification of stereo-
                            chemistry. It is isolated as a pure substance from natural sources and gives no
                            indication of being a mixture of stereoisomers. Although it is not optically active,
                            it does not appear to be a racemic mixture, because it does not yield separate peaks
                            on chiral HPLC columns. When completely hydrolyzed, it yields racemic nonactic
                            acid. Deduce the stereochemical structure of nonactin from this information.
                                        CH 3          O
                                                                                   CH 3
                                        O       O      O             CH 3
                                                                                        2
                                      O           CH 3    CH            HO  H  O  H  CO H
                                           CH 3             3
                                                                          nonactic acid
                                          O          O
                                   CH 3
                                            CH 3  CH 3    O
                                       O
                                               O
                                                       O
                                        O
                                                     CH 3
                                                                      1
                       2.16. (a) The signals for the benzylic hydrogens in the H NMR spectra of the cis
                            and trans isomers of 1-benzyl-2,6-dimethylpiperidine have distinctly different
                            appearances, as shown in Figure 2.16Pa. Answer the following questions about
                            these spectra: (a) Which isomer corresponds to which spectrum and why do
                            they have the appearances they do? (b) Only one isomer shows a multiplet
                            corresponding to ring C−H hydrogens adjacent to nitrogen near 3 ppm. Why
                                                                                          1
                            are these signals not visible in the other partial spectrum? (b) The partial H
                            NMR spectra corresponding to each benzyl ether of the diastereomeric 2,6-
                            dimethylcyclohexanols are shown in Figure 2.16Pb. Assign the stereochemistry
                            of each isomer.
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